CODEWITHSUNDEEP
arraysruby
user6820969
user6820969

Reputation:

Converting string into an array

I have a string: 

key = "41521"

And I want to convert it into an array like this:

array = [41, 15, 52, 21]

I went about it like so:

array = []
array << key[0..1].to_i
array << key[1..2].to_i
array << key[2..3].to_i
array << key[3..4].to_i

What would be a better way?

Upvotes: 0

Views: 131

Answers (4)

Cary Swoveland
Cary Swoveland

Reputation: 110755

key = "41521"

key.each_char.each_cons(2).map { |a| a.join.to_i }
  #=> [41, 15, 52, 21]

or

key.gsub(/\d(?=(\d))/).with_object([]) { |s,a| a << (s<<$1).to_i }
  #=> [41, 15, 52, 21]

or

a = []
e = key.each_char
  #=> #<Enumerator: "41521":each_char>
loop { a << (e.next << e.peek).to_i }
a #=> [41, 15, 52, 21]

In #3 Enumerator#peek raises a StopInteration exception when the internal position of the enumerator is at the end (unless key is an empty string, in which case Enumerator#next raises the StopInteration exception). Kernel#loop handles the exception by breaking out of the loop.

Upvotes: 6

vol7ron
vol7ron

Reputation: 42169

Not as short as some other answers, but for me, more easier to see the steps:

arr = key.chars.each_with_index
         .reduce([]) {|s,(v,i)| s << (v + (key[i+1] || '')).to_i }
         .select {|s| s.to_s.length > 1 }

# arr: [41, 15, 52, 21]

Upvotes: 1

sawa
sawa

Reputation: 168259

key.gsub(/(?<=.)\d(?=.)/, '\&\&').scan(/\d{2}/).map(&:to_i)
# => [41, 15, 52, 21]

or

(0...key.length).map{|i| key[i, 2].to_i}
# => [41, 15, 52, 21, 1]

Upvotes: 2

Hieu Phan
Hieu Phan

Reputation: 1

(0..(key.length-2)).map{|i| key.slice(i, 2)}

Upvotes: 0

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