CODEWITHSUNDEEP
c++serializationboostreferencedefault-constructor
topright gamedev
topright gamedev

Reputation: 2665

Deserialize object with references and no default constructor (boost::serialization)

Is it possible in boost::serialization library to deserialize (polymorphic) objects with references and no default constructor?

class Example
{
    int& value;

public:

    Example(int _value): value(_value) {}
    virtual ~Example() {}

    friend class boost::serialization::access;
    template<typename Archive>
    void serialize(Archive & ar, const unsigned int file_version)
    {
        ar & value;
    }
};

class Usage
{
    Example* example;

public:

    Usage(): example(new Example(123)) {}
    ~Usage() { delete example; }

    friend class boost::serialization::access;
    template<typename Archive>
    void serialize(Archive & ar, const unsigned int file_version)
    {
        ar & example;
    }
};

...

// serialize and deserialize object with reference and no default constructor
{
    Usage source;

    std::ostringstream oss;
    boost::archive::text_oarchive oa(oss);
    oa & source;

    Usage target;

    std::istringstream iss(oss.str());
    boost::archive::text_iarchive ia(iss);
    ia & target; // does not compile
}

Upvotes: 2

Views: 2481

Answers (1)

Ise Wisteria
Ise Wisteria

Reputation: 11659

As for non-default constructible object, I'd recommend to look the item Non-Default Constructors here.
Your class can be serialized by writing your own function template load_construct_data and save_construct_data.

Upvotes: 5

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