CODEWITHSUNDEEP
svncommand-line
Ian Barkley-Yeung
Ian Barkley-Yeung

Reputation: 151

SVN: How can I list all the files in a changelist in Subversion?

How can a get a list of files in an SVN changelist with NO information except the file list?

I want a listing of files in a changelist in a format that I can use in Bash's $(). I start with svn st --cl 3011, which lists the files but with a lot of extra junk:

Performing status on external item at 'foo'

? foo/bar

Performating status on external item at 'foo/bar'

--- Changelist '3011':

M src/math/math.cc

A src/math/determinant.cc

A src/math/determinant.h

M src/math/matrix.h

That's a lot of info to try and get sed or awk to parse through, and I'm worried I'll mess it up and end up missing a file in the changelist or adding stuff that's not in the changelist. -q doesn't help much.

Is there any way get svn to just give me src/math/math.cc src/math/determinant.cc src/math/determinant.h src/math/matrix.h?

Thanks, Ian

Upvotes: 10

Views: 13225

Answers (5)

Hemant Sharma
Hemant Sharma

Reputation: 149

svn log -r <revision_number> -v

Upvotes: -1

Jimbo
Jimbo

Reputation: 26624

Use --ignore-externals and --cl!

You don't need to use any external tools like grep or awk. This is actually pretty simple!

The command --ignore-externals removes all the extra junk from the svn status call, and you can easily merge that with --cl parameter too:

svn st --ignore-externals --cl "Changelist Name"

That will ignore all externals, and then give you just the files in the changelist you ask for.

Upvotes: 3

user1633977
user1633977

Reputation: 111

This will do: 

svn st --changelist 3011 | grep -v Changelist | cut -b 3-

svn st --changelist will print the name of the changelist plus the status of the files and the file names:

--- Changelist 'cl_name':
M       file1
A       file2

Now you edit this by first deleting the first line with a "grep -v Changelist", which deletes the line with the word Changelist. Then do a "cut -b 3-" to delete the first few characters of each line.

With the full command, you get:

 file1
 file2

Upvotes: 6

pmod
pmod

Reputation: 11007

As for as I know there is no direct way (only with svn arguments) to do what you want. However, you can rely on output of svn stat -v, and on that path starts from 41 position. For only immidiates the following perl one-liner do the task:

perl -e "@st=`svn stat -v -N`;foreach $l (@st){print substr($l,41);}"

For recursive status just remove -N from svn arguments.

In addition to printing out all contents of the directoty you may want to separate modified files, files not under svn, by revision, etc. In this case you can easily modify my above script using the substr(0,1) - first char of each output. For example, the following one-liner will output list of only modified files:

perl -e "@st=`svn stat -v -N`;foreach $l (@st){print substr($l,41) if substr($l,0,1) eq "M";}"

Upvotes: 0

AlG
AlG

Reputation: 15167

If you don't mind going one directory at a time you can do per directory:

svn status lib | awk '{print $2}'

Where you swap out lib for the dir in question.

Upvotes: 1

Related Questions