Reputation: 755157
I have a JSON serialization problem and I hope someone here might have an idea how to solve it.
I am working with an older application that uses a lot of "magic strings" for statuses etc., which are defined as
public const string StatusActive = "active";
public const string StatusRetired = "retired";
In the SQL Server database table, I am storing the actual string representation.
This is OK - but a bit messy. So I decided to create wrapper classes around those constants, to ensure only valid strings will be used etc. These looks someting like this:
public class StatusWrapper {
public const string Active = "active";
public const string Retired = "retired";
private readonly string _value;
public string Value
{
get { return _value; }
}
public StatusWrapper(string value)
{
switch (value)
{
case Active:
case Retired:
_value = value;
break;
default:
throw new ArgumentException($"Invalid status:={value}");
}
}
.....
}
This works fine - now I can capture each status into a StatusWrapper
instance, and ensure no invalid "magic strings" are used.
But when it comes to JSON serialize a DTO which contains one of these StatusWrapper
classes, I would like to have just a single "JSON property" in the form of
"status":"active"
in my JSON - but since it's a separate object instance, I now get
"statusWrapper" : { "value":"active" }
Is there any trick to JSON serialize my StatusWrapper
class as just a single JSON property?
I tried using a custom JSON converter:
public class StatusWrapperSerializer : JsonConverter
{
/// <inheritdoc />
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) {
var statusWrapper = value as statusWrapper;
// writer.WriteStartObject();
writer.WritePropertyName("status");
serializer.Serialize(writer, statusWrapper.Value);
// writer.WriteEndObject();
}
....
}
but when I decorate my StatusWrapper
class with this customer serializer, hoping to get just a single JSON property back, I instead get an error:
Message=Token PropertyName in state Property would result in an invalid JSON object. Path ''.
Is there a way to JSON serialize a "wrapper" class into a single JSON property? And if so: HOW?
Upvotes: 1
Views: 2302
Reputation: 759
You must write only the value (not both property name and the value) in WriteJson method.
Try:
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) {
var statusWrapper = (StatusWrapper)value;
writer.WriteValue(statusWrapper.Value);
}
Upvotes: 4