CODEWITHSUNDEEP
pythondictionary
Krish V
Krish V

Reputation: 546

Count number of dictionaries in list satistying condition on value

How do I get the number of dictionaries where value satisfies a given condition?

list_of_dict = [
                   {'seq_no': 10, 'file_path': 'file/path', 'rel_item': None},
                   {'seq_no': 22, 'file_path': 'file/path', 'rel_item': 0},
                   {'seq_no': 32, 'file_path': 'file/path', 'rel_item': 0},
                   {'seq_no': 90, 'file_path': 'file/path', 'rel_item': 0},
                   {'seq_no': 10, 'file_path': 'file/path', 'rel_item': None},
 ]

I would like to count the number of dictionaries where key rel_item=None.

Upvotes: 0

Views: 3915

Answers (4)

Sohaib Farooqi
Sohaib Farooqi

Reputation: 5666

You can filter the list_of_dict based on your criteria

>>> len(list(filter(lambda x: x['rel_item'] is None, list_of_dict)))
>>> 2

Upvotes: 1

BENY
BENY

Reputation: 323286

You can using map then 

sum((map(lambda x : x['rel_item'] is None,list_of_dict)))
Out[721]: 2

Upvotes: 0

jpp
jpp

Reputation: 164693

Here is one way.

c = sum(i['rel_item'] is None for i in list_of_dict)
# 2

Upvotes: 4

Yilun Zhang
Yilun Zhang

Reputation: 9018

This will do the job:

len([x for x in list_of_dict if x["rel_item"] == None])

Upvotes: 1

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