Reputation: 4416
If I had a function like this:
foo <- function(var) {
if(length(var) > 5) stop("can't be greater than 5")
data.frame(var = var)
}
Where this worked:
df <- 1:20
foo(var = df[1:5])
But this didn't:
foo(var = df)
The desired output is:
var
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
10 10
11 11
12 12
13 13
14 14
15 15
16 16
17 17
18 18
19 19
20 20
If I know that I can only run this function in chunk of 5 rows, what would be the best approach if I wanted to evaluate all 20 rows? Can I use purrr::map()
for this? Assume that the 5 row constraint is rigid.
Thanks in advance.
Upvotes: 0
Views: 103
Reputation: 47330
You can use dplyr::group_by
or tapply
:
data.frame(df) %>%
mutate(grp = (row_number()-1) %/% 5) %>%
group_by(grp) %>%
mutate(var = foo(df)$var) %>%
ungroup %>%
select(var)
# # A tibble: 20 x 1
# var
# <int>
# 1 1
# 2 2
# 3 3
# 4 4
# 5 5
# 6 6
# 7 7
# 8 8
# 9 9
# 10 10
# 11 11
# 12 12
# 13 13
# 14 14
# 15 15
# 16 16
# 17 17
# 18 18
# 19 19
# 20 20
data.frame(var=unlist(tapply(df,(df-1) %/% 5,foo)))
# var
# 01 1
# 02 2
# 03 3
# 04 4
# 05 5
# 11 6
# 12 7
# 13 8
# 14 9
# 15 10
# 21 11
# 22 12
# 23 13
# 24 14
# 25 15
# 31 16
# 32 17
# 33 18
# 34 19
# 35 20
Upvotes: 0
Reputation: 28391
We split
df
in chunks of 5 each then use purrr::map_dfr
to apply foo
function on them then bind
everything together by rows
library(tidyverse)
foo <- function(var) {
if(length(var) > 5) stop("can't be greater than 5")
data.frame(var = var)
}
df <- 1:20
df_split <- split(df, (seq(length(df))-1) %/% 5)
df_split
map_dfr(df_split, ~ foo(.x))
var
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
10 10
11 11
12 12
13 13
14 14
15 15
16 16
17 17
18 18
19 19
20 20
Upvotes: 1