Reputation: 173
I'm having trouble understanding the behaviour of a small sample customer Akka Streams Source.
The idea behind the sample is that the Source should ask an Actor for the next element. See the code below
class ActorSource[T](context: ActorRefFactory, actor: ActorRef) extends GraphStage[SourceShape[T]] {
val out: Outlet[T] = Outlet("actor-source")
override def createLogic(inheritedAttributes: Attributes): GraphStageLogic = {
new GraphStageLogic(shape) {
setHandler(out, new OutHandler {
val receivingActor = context.actorOf(Props(new ReceivingActor(msg => {
push(out, msg)
println("push - Done")
})))
override def onPull(): Unit = {
actor ! Protocol.Pull(receivingActor)
println("onPull - Done")
}
})
}
}
override def shape: SourceShape[T] = SourceShape(out)
/**
* A small actor which receives new elements from the actual source actor.
*
* @param push The method to push elements into the stream
*/
class ReceivingActor(push: T => Unit) extends Actor with ActorLogging with UnknownMessage {
override def receive: Receive = {
case Protocol.Push(msg) =>
push(msg.asInstanceOf[T]) // I know that this is evil ....just for test in that case...
case msg =>
unknownMessage(msg)
}
}
}
object ActorSource {
/**
* Creates an [[ActorSource]]
*
* @param actor The actor which acts as the source
* @param context The context to create the internal helper actor
* @return A new akka-streams source
*/
def Source[T](actor: ActorRef)(implicit context: ActorRefFactory): AkkaSource[T, NotUsed] = {
val graph: Graph[SourceShape[T], NotUsed] = new ActorSource[T](context, actor)
AkkaSource.fromGraph(graph)
}
/**
* Defines the messages/ events for the source actor
*/
object Protocol {
/**
* Will be sent if the stream requires new elements.
*
* @param actor The actor which should receive the push message
*/
case class Pull(actor: ActorRef)
/**
* Sent by the source actor to submit a new element.
*
* @param msg The message to put into the stream.
*/
case class Push(msg: Any)
}
}
If you create a stream with that source like this one:
class SampleActor extends Actor with ActorLogging with UnknownMessage {
var counter = 0
override def receive: Receive = {
case msg @ Protocol.Pull(actor) =>
actor ! Protocol.Push(counter)
counter = counter + 1
}
}
val sourceActor = system.actorOf(Props(new SampleActor()))
val stream = ActorSource
.Source[Int](sourceActor)(system)
.take(10)
.runWith(Sink.foreach(println))
Await.result(stream, 30 seconds)
The output is only as follows:
onPull - Done
push - Done
The first integer never reaches the Sink and onPull
is not called anymore. What is interesting, if I kill the programm the first integer is printed in the Sink.
I'm wondering if this is a feature or a bug? From what I understood one can call push(_, _)
anytime after one pull
signalled that the outlet is open, even if I ask for isAvailable
it returns true
.
Can anyone explain that behaviour?
Upvotes: 1
Views: 439
Reputation: 173
After reading more in the docs (RTFM ;)) I think I found the answer to my question.
It is mentioned in multiple places that it‘s not safe to call these API methods outside the related callbacks. To achieve what I was going to achieve Akka Streams provides a getAsyncCallback
method.
More details can be found here: https://doc.akka.io/docs/akka/2.5.4/scala/stream/stream-customize.html#using-asynchronous-side-channels.
Upvotes: 0