CODEWITHSUNDEEP
python
Karma
Karma

Reputation: 269

list index out of range using get()

I got an error of 'list' object has no attribute 'get'. Usually, it worked fine,

weather_1D_ago = data['city']['weather']['daily'][0]['actual']['fmt']
weather_2D_ago = data['city']['weather']['daily'][1]['actual']['fmt']

'city': {'weather': {'daily': [{'actual': {'fmt': '1.2',
                                           'raw': 1.2},
                                'date': '1D_ago',
                                'estimate': {'fmt': '1.3',
                                             'raw': 1.3}},
                               {'actual': {'fmt': '2.2',
                                           'raw': 2.2},
                                'date': '2D_ago',
                                'estimate': {'fmt': '2.3',
                                             'raw': 2.3}},,

Until the path was missing, as shown below:

'city': {'weather': {'daily': []},

Update: I tried to use .get() to achieve the data, and make it return as None if the value is missing.

weather_1D_ago = data['city']['weather'].get('daily', {})[0].get('actual', {}).get('fmt', {})
weather_2D_ago = data['city']['weather'].get('daily', {})[1].get('actual', {}).get('fmt', {})

But I just got an error of list index out of range

I'd avoid using try-except blocks because it will mix up my other codes when referred to weather_1D_ago and another error will generate: local variable 'weather_1D_ago' referenced before assignment

So, how would you make it return None using .get() even if the path is not valid? Thanks!

Upvotes: 0

Views: 92

Answers (1)

yausername
yausername

Reputation: 760

def safe_list_get(l, i):
    if l and i < len(l):
        return l[i]
    return {}

weather_1D_ago = safe_list_get(data['city']['weather'].get('daily', []),0).get('actual', {}).get('fmt', {})
weather_2D_ago = safe_list_get(data['city']['weather'].get('daily', []),1).get('actual', {}).get('fmt', {})

Upvotes: 1

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