CODEWITHSUNDEEP
bashshell
user3321425
user3321425

Reputation: 201

Compare filenames (without extension) from "Dir1" to subfolder "Dir2" assuming I'm at "Dir1"

I'm trying to compare Dir1 and Dir2 file names without extension. Dir2 is a subfolder of Dir1 so I'm launching the script from Dir1.

Dir1/proof1.txt
Dir1/proof2.txt
Dir1/proof3.txt
Dir1/proof4.txt
Dir1/proof5.txt
Dir1/proof6.txt

Dir1/Dir2/proof1.png
Dir1/Dir2/proof2.png
Dir1/Dir2/proof5.png

And the output I wanted is the file names that exists at Dir1 but not at Dir2:

proof3
proof4
proof6

This is what I'm using (not working) to find Files that are at Dir1 but not at Dir2:

(find . -printf '%P\n' | grep -v Dir2 && find Dir2/ -printf '%P\n' && find Dir2/ -printf '%P\n') | sort | uniq -u

Upvotes: 0

Views: 45

Answers (2)

user unknown
user unknown

Reputation: 36269

Only testet with clean filenames without whitespace:

for f in proof*.txt ; do test -f "Dir2/$(basename "$f" .txt).png" || echo no match "$f"; done
  • Test -f tests, if a file exists and is an ordinary file.
  • basename removes the extension, if given

Upvotes: 1

karakfa
karakfa

Reputation: 67567

this should do...

$ comm -23 <(ls -1 | cut -d. -f1) <(ls -1 Dir2/ | xargs -n 1 basename | cut -d. -f1)

may not work as intended if your filenames have . in them other than separating extension.

Upvotes: 0

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