CODEWITHSUNDEEP
linuxshellsedtext-processing
user1594099
user1594099

Reputation: 35

Search and replace URL in all files

I'm looking to run script or command to mass change a string that is a URL. I've viewed many examples on this forum, however none are working.

I have created a .sh file to run the following:

$SRC='$url = "https://www.myurl.com/subdir/process.do"';
$DST='$url="https://api.myurl.com/subdir/process.do"';
find . -type f -name "*.php" -exec sed -i 's/$SRC/$DST/g' {} +;

This is not working. I'm thinking it may because of having backslashes in the search content? The search/replace is needed to be run across all sub-directories on .php files.

Any assistance would be greatly appreciated.

Thanks!

Upvotes: 1

Views: 2950

Answers (1)

Linux Pro
Linux Pro

Reputation: 468

First thing - check your variable definitions. In bash, variable definitions usually do not start with a leading $. Ie, should be:

SRC='$url = "https://www.myurl.com/subdir/process.do"';
DST='$url="https://api.myurl.com/subdir/process.do"';

Next, you should switch to using single quotes for the pattern, and double quotes for the variable, as per: https://askubuntu.com/questions/76808/how-do-i-use-variables-in-a-sed-command

Example that seems to work:

sed -i 's,'"$SRC"','"$DST"','

UPDATE: This exact script works perfectly for me on Linux:

 #!/bin/bash
 SRC='$url = "https://www.myurl.com/subdir/process.do"'; 
 DST='$url="https://api.myurl.com/subdir/process.do"';
 find . -type f -name "*.php" -exec sed -i 's,'"$SRC"','"$DST"',' {} \;

Contents of file "asdf.php" created in home directory (before running script):

 $url = "https://www.myurl.com/subdir/process.do"

Contents of file "asdf.php" after running script:

 $url="https://api.myurl.com/subdir/process.do"

Upvotes: 1

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