Reputation: 13
I had to test if my machine is using the little or the big endian. For this reason i wrote this code. I can see that my machine is using the little endian. But i dont know why the output from my first byte is only D. Should it not be 0D?
union int2byte
{
unsigned char bytes[4];
unsigned int hex;
};
int main(int argc, const char* argv[])
{
union int2byte hexby;
hexby.hex = 0xBAADF00D;
printf("%u\n",hexby.hex);
int counter;
for(counter = 0; counter < 4; counter = counter + 1)
{
printf("Hex for Byte %u is %X.\n",counter+1, hexby.bytes[counter]);
}
}
Output:
3131961357
Hex for Byte 1 is D.
Hex for Byte 2 is F0.
Hex for Byte 3 is AD.
Hex for Byte 4 is BA.
Upvotes: 1
Views: 787
Reputation: 595887
%X
does not output leading zeros. Use %02X
instead. The 2
tells it to output at least 2 digits, and the 0
tells it to pad the output on the left side with a '0'
character if the output is less than 2 digits.
Upvotes: 5