Reputation:
len = 5
results = np.empty(len)
for i in range(len):
results[i] = ([999, 'sss'])
I would like to predefine the length of a list, which is 5 and then fill in some values which contains both numerical and string variables... However, whatever I use
for i in range(len):
results[i] = ([[999], ['sss']])
or
for i in range(len):
results[i] = [[999], ['sss']]
I got error message as
ValueError Traceback (most recent call last)
<ipython-input-114-4cfd5264742d> in <module>()
2 results = np.empty(len)
3 for i in range(len):
----> 4 results[i] = ([999, 'sss'])
ValueError: setting an array element with a sequence.
How should i do?
Upvotes: 0
Views: 164
Reputation: 231385
Unless you really have a need for a numpy array with mixed dtype
, I'd recommend making a list of lists:
In [96]: alist = []
In [97]: for i in range(5):
...: alist.append([999, 'sss'])
...:
In [98]: alist
Out[98]: [[999, 'sss'], [999, 'sss'], [999, 'sss'], [999, 'sss'], [999, 'sss']]
Or if you make a list of tuples, you can go on an make a structured array - 1d with 2 fields of the desired dtype
:
In [99]: alist = []
In [100]: for i in range(5):
...: alist.append((999, 'sss'))
...:
...:
In [101]: alist
Out[101]: [(999, 'sss'), (999, 'sss'), (999, 'sss'), (999, 'sss'), (999, 'sss')]
In [102]: np.array(alist, dtype='int,U3')
Out[102]:
array([(999, 'sss'), (999, 'sss'), (999, 'sss'), (999, 'sss'),
(999, 'sss')], dtype=[('f0', '<i8'), ('f1', '<U3')])
When trying to mix integers and strings you need to pay attention to the intended use.
Note what happens when you create an 'empty' array:
In [103]: arr = np.empty(4)
In [104]: arr
Out[104]: array([0.e+000, 0.e+000, 0.e+000, 5.e-324])
In [105]: arr.dtype
Out[105]: dtype('float64')
It creates an array of the desired size, but with a default dtype
, float
. The initial values are garbage - though displayed as floats.
That means that the only thing you can put in arr[0]
is a float.
In [106]: arr[0]=999 # converted to float
In [107]: arr[1]='sss'
...
ValueError: could not convert string to float: 'sss'
In [108]: arr
Out[108]: array([9.99e+002, 0.00e+000, 0.00e+000, 4.94e-324])
And it won't accept a list or tuple either, a sequence. It has to be something that can be converted to a float.
Specifying an object
dtype does let you put anything in elements, because the elements actually hold pointers - just like a list.
In [110]: arr = np.empty(4,dtype=object)
In [111]: arr
Out[111]: array([None, None, None, None], dtype=object)
In [112]: arr[0]=1
In [113]: arr[1]=.999
In [114]: arr[2]='sss'
In [115]: arr[3]=[999,'sss']
In [116]: arr
Out[116]: array([1, 0.999, 'sss', list([999, 'sss'])], dtype=object)
Such an array is either a glorified list, or a debased one, depending on your needs.
Upvotes: 1
Reputation: 51335
you could use the dtype
'object'
for your results
array:
length = 5
results = np.empty(length, dtype='object')
for i in range(length):
results[i] = ([999, 'sss'])
>>> results
array([list([999, 'sss']), list([999, 'sss']), list([999, 'sss']),
list([999, 'sss']), list([999, 'sss'])], dtype=object)
If what you're putting into your results
array is always of length 2, better to specify the appropriate shape when you make your np.empty
:
length = 5
results = np.empty((length,2), dtype='object')
for i in range(length):
results[i] = ([999, 'sss'])
>>> results
array([[999, 'sss'],
[999, 'sss'],
[999, 'sss'],
[999, 'sss'],
[999, 'sss']], dtype=object)
Note, try not to use len
as a variable, as it is already a built-in function in python (I replaced it with length
in my examples above)
Upvotes: 2