CODEWITHSUNDEEP
phpcodeigniter
Agha
Agha

Reputation: 411

date conversion in CodeIgniter / PHP does not gives output

I have date in this type of format: April 1st 2017 and I want to convert it into this type of format: 2017/04/01 in my CodeIgniter code using php. I have used below posted piece of code but it is not working. Please solve the issue.

Code:

$date = DateTime::createFromFormat('m/d/Y', "April 1st 2017");
echo "Date = ".$date->format('Y-m-d');

Upvotes: 1

Views: 735

Answers (4)

PHP Geek
PHP Geek

Reputation: 4033

you can try this also

<?php
$date='22 march 2018';
 echo date('m/d/Y', strtotime($date));
?>

Upvotes: 0

Alvin Karpis
Alvin Karpis

Reputation: 1

The format you specified for your date is incorrect.

It would convert '04/01/2017' but it does not suit April 1st 2017.

Try instead: createFromFormat('F dS Y')

Explanation:

F - full textual representation of a month, such as January.

d - day

S - English ordinal suffix for the day of the month

Y - 4-digit representation of year

Upvotes: 0

Gufran Hasan
Gufran Hasan

Reputation: 9373

You can use strtotime() and date() php functions as

$newDate = date("m/d/Y", strtotime("April 1st 2017"));

Or in CodeIgniter

$date = DateTime::createFromFormat('j F Y - H:i', 'April 1st 2017');
echo $date->format('m/d/Y H:i:s');

Upvotes: 1

Syscall
Syscall

Reputation: 19780

Your format can be used in the constructor of DateTime. See accepted formats.

$date = new DateTime("April 1st 2017");
echo "Date = ".$date->format('Y-m-d');

Outputs:

Date = 2017-04-01

If you want to use DateTime::createFromFormat(), you have to use the proper format 

"F jS Y"

Upvotes: 0

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