CODEWITHSUNDEEP
pythonfor-loop
begincoding123
begincoding123

Reputation: 161

python - adding each digit that is greater than 4

Given an integer. for each individual digit that is greater than 4, i need to add it to all the next digits that greater than 4. For example: a = 4567; the result should be 0 + (5) + (5+6) + (5+6+7) = 34 So far in my code, I was able to get the sum for single digit only. If the integer is greater 10, it will only give the sum of the very first digit. Any idea why this happening? 

def morethanfour(number):
    num = 0
    num = [int(d) for d in str(number)] #seperate into individual digit  
    total = 0
    for i in range (len(num)):
        if num[i] > 4:
            total = sum(x for x in range(5, num[i]+1)) #adding the sum

    return total


num = 9
print(morethanfour(num))

the result when num = 9 is 35 (5+6+7+8+9) However, when num = 178, it gave me 0

Upvotes: 0

Views: 950

Answers (2)

mshsayem
mshsayem

Reputation: 18018

Try this:

>>> def morethanfour(number):
        return sum(sum(range(5,x+1)) for x in map(int,str(number)) if x>4)

>>> morethanfour(9)
35
>>> morethanfour(4567)
34
>>> morethanfour(178)
44

Upvotes: 2

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 799230

>>> sum(sum(num[j] for j in range(0, i+1) if num[j] > 4) for i in range(len(num)))
34

Upvotes: -1

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