CODEWITHSUNDEEP
phpvariablesechophp-5.3heredoc
delaccount992
delaccount992

Reputation: 1333

PHP error when attempting to print variables within an echo using heredoc

When I try to do this:

var $example = "Example";
echo <<<EOT
<p>$example</p>
EOT;

I get this error:

Parse error: syntax error, unexpected T_VAR in ..... on line ...

What is going on here?? To my knowledge this should work.

I'm using PHP 5.3.5.

Upvotes: 0

Views: 365

Answers (4)

delaccount992
delaccount992

Reputation: 1333

D'oh. Removing the 'var' keyword fixed it. Thanks for the input guys!

Unfortunately however it didn't solve my actual problem. See here:

$param = array_merge($_REQUEST, $_FILES, $_COOKIE);

$param['example'] = "example";

example();

function example()
{
    global $param;
    echo <<<EOT
        <p>$param['example']</p>
EOT;
    return;
}

This time the complaint is:

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in ..... on line ...

Again, what is going on here?

Upvotes: 0

Oswald
Oswald

Reputation: 31685

The var keyword on the first line is for declaring variables in classes only. Leave it out.

Upvotes: 5

Mchl
Mchl

Reputation: 62395

There is no keyword var in PHP. Not in PHP5 anyway - it's only accepted due to backward compatibility, and is used to define class variables.

Upvotes: 1

Foo Bah
Foo Bah

Reputation: 26281

remove the word var.

see http://www.php.net/manual/en/language.variables.basics.php

Upvotes: 3

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