CODEWITHSUNDEEP
makefileexit-code
Suanmeiguo
Suanmeiguo

Reputation: 1405

Have make command exit 1

I'm trying to throw an error with Make command. This is my makefile:

exit:
    val=1
    exit $(val)

However, when I run make exit && echo $? it gave me exit code 0. I was expecting exit code 1.

Did I use it wrong? Appreciate it.

Upvotes: 4

Views: 6583

Answers (1)

l0b0
l0b0

Reputation: 58768

  1. Makefile target "scripts" are not run like real scripts, instead each command is run in a separate shell.
  2. You need to escape dollar signs in makefiles by using an extra dollar sign.
  3. There is a fundamental difference between makefile variables, declared outside of targets and referenced using $(name), and shell variables, declared as part of a command inside a target and referenced using $${name}.

What you want is either a single command equivalent to val=1 && exit $val:

exit:
    val=1 && exit $${val}

or a makefile variable used in a simple command:

val = 1
exit:
    exit $(val)

Upvotes: 4

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