CODEWITHSUNDEEP
scala
Rjj
Rjj

Reputation: 297

Scala. How to take the count of array of first array using scala

I have a file with words separated by * and lines separated by ~, I would like to count the specific word how many times it is appeared in the file.

For eg.

Input File:

AB*xyz*1234~
CD*mny*769~
MN*bvd*2345~
AB*zar*987~

Code:

for (line <- bufferedSource.getLines()) {
      array = line.split("\\~")

for (row <- array ){
      val splittedRow=row.split("\\*")
      val cnt = splittedRow(0).contains("AB").count()

Here i am facing the issue in, how many times the word AB is present. Can you please help me how to get the count of specific words from an array. I am not able to use the keyword .count.

Kindly help me.

Upvotes: 0

Views: 149

Answers (3)

SourceCodeBot
SourceCodeBot

Reputation: 175

I made a small function for your case:

def count(term:String,file:File): Int = {
    Source.fromFile(file, "UTF-8").getLines().foldRight(0)((line, count) => {
        count + line.split("\\*").filter(_.contentEquals(term)).length
    })
}

println(count("AB",PATH_TO_INPUT)) // result is 2

all lines will check if there is your delimitter, filter the list of words to the term and add the length of remaining words to the current count value.

this helps me to understand fold methods

I hope that answer your question

Upvotes: 1

Ramesh Maharjan
Ramesh Maharjan

Reputation: 41957

the issue in, how many times the word AB is present. Can you please help me how to get the count of specific words from an array

You can read the file using Source api and then store the separated words in a list. 

val resultArray = Source.fromFile(filename).getLines().flatMap(line => line.replace("~", "").split("\\*")).toList

You can count the number of repeatition of each words by call count function as 

println(resultArray.count(_ == "AB"))   //will print 2
println(resultArray.count(_ == "CD"))   //will print 1
println(resultArray.count(_ == "xyz"))  //will print 1

I hope the answer is helpful

Upvotes: 0

chengpohi
chengpohi

Reputation: 14217

arr.map(_.split("\\*")).count(i => i.headOption.exists(_.contains("AB")))

count by contains function with first element and use Option to handle None.

Upvotes: 0

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