Reputation: 25
def Corner(n):
if n == 3:
print('İts An Triangle \nBu Bir Üçgen')
elif n == 4:
print('İts An Rectangle or Square or Parrallelogram \nBu Bir
Dikdörtgen yada Kare yada ParalelKenar ')
elif n == 5:
print('İts An Pentagon \nBu Bir Beşgen')
elif n == 6:
print('İts An Hexagon \nBu Bir Altıgen')
else:
print('Bir Köşe Sayısı Girmediniz \nYou Didnt Wrote a Corner
Number '
print Corner(6)
**File "Köşegen.py", line 13
print Corner(6)
^
SyntaxError: invalid syntax**
Its The Error Code I wrote it on Python3 This Code About the Corners and Shapes but I had that massage when I run the code
Upvotes: 0
Views: 301
Reputation: 25
I'm Closed The Parantheses and Its Worked Thanks For Help Artemis Fowl and Todd W
def Corner(n):
if n == 3:
print('İts An Triangle \nBu Bir Üçgen')
elif n == 4:
print('İts An Rectangle or Square or Parrallelogram \nBu Bir
Dikdörtgen yada Kare yada ParalelKenar')
elif n == 5:
print('İts An Pentagon \nBu Bir Beşgen')
elif n == 6:
print('İts An Hexagon \nBu Bir Altıgen')
else:
print('Bir Köşe Sayısı Girmediniz \nYou Didnt Wrote a Corner Number')
print(Corner(6))
Upvotes: 0
Reputation: 2711
In python 3, print is a function just like any other, so you need parentheses, as below:
print(' something ')
Rather than:
print ' something '
In python 2
Upvotes: 0
Reputation: 397
You're missing some parentheses:
print('Bir Köşe Sayısı Girmediniz \nYou Didnt Wrote a Corner Number ') # here
print(Corner(6)) # and here
Upvotes: 2