CODEWITHSUNDEEP
c++
Pushkar Mahajan
Pushkar Mahajan

Reputation: 130

What is the meaning of *table[17]?

What is *table[17] in the given code? Does it just make 17 copies of the structure?

struct node
{
  string key;
  string no;
  node *next;
}*table[17];

Upvotes: 0

Views: 58

Answers (2)

Abhijit Pritam Dutta
Abhijit Pritam Dutta

Reputation: 5591

What is *table[17]?

The meaning of this line of code ...}*table[17]; is, you have defined a struct node and declared an array of type node pointer and size of that pointer array is to store 17 node element/object pointers. So in table array you can store the address of 17 node elements.

For example:-

    struct node a, b, c, d ....,p;         
    table[0] = &a;//storing the address of a;
    table[1] = &b;//storing the address of b;
    table[2] = &c;//storing the address of c;
    .
    .
    .
    table[16] = &p;//storing the address of p;

or dynamically:-

      for( int i = 0; i < 17; i++)
          table[0] =  new node();// in C (struct node *) malloc(sizeof(struct node));

Does it just make 17 copies of the structure?

No it is just an array of 17 pointers. You have to assign the address of element of type node in each location. Hence you have to create each node element like I did above. Hope this will help you.

Upvotes: 2

eerorika
eerorika

Reputation: 238341

What is the meaning of *table[17]?

It is a declarator. It declares a variable of type *node[17] with name table. That is an array of 17 pointers to node.

Does it just make 17 copies of the structure?

No. No node objects will be made.

Upvotes: 5

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