CODEWITHSUNDEEP
javaandroidfirebasefirebase-realtime-database
Christoffer Krabbe
Christoffer Krabbe

Reputation: 1

Retrieving data from Firebase when the parent of the child node is unknown

I am building an app where you can send and get friend request. The database is structured as:

link to image

Now I want to build an "alert function" when someone sends you a friend request with an addValueEventListener so that I can see if the current user have a "recieved" in the database. Something like: 

mFriendRequestDatabase = 
FirebaseDatabase.getInstance().getReference().child("Friend_req");
    mCurrent_user = FirebaseAuth.getInstance().getCurrentUser();
    String current_user_id = mCurrent_user.getUid();
    mFriendRequestDatabase.child(current_user_id).addValueEventListener(new 
ValueEventListener() {
        @Override
        public void onDataChange(DataSnapshot dataSnapshot) {


        }

        @Override
        public void onCancelled(DatabaseError databaseError) {

        }
    });

The problem is that i can't reach to see if current user have a "sent" or a "recieved" since i don't know the ID of the person that sent the request. dataSnapshot.child(???).child("sent" or "recieved")

How to I solve this problem?

Upvotes: 0

Views: 202

Answers (1)

Frank van Puffelen
Frank van Puffelen

Reputation: 598728

You could get some of this with a query, but it'll be tricky to keep the performance under control since you'll need to define an index on every user. For some of the problems with this see my answers here, and here.

A better way is to separate the requests into two separate lists: the ones that were sent, and the ones that were received. E.g.

friend_requests
  uidOfChristoffer
    received
      uidOfPuf: true
    sent:
      uidOfSomeoneElse: true
 uidOfPuf
    sent
      uidOfChristoffer: true
 uidOfSomeoneElse
    received
      uidOfChristoffer: true

Now you can specifically get the ones that anyone has received by reading /friend_requests/theirUid/received. This is a more specific approach of a many-to-many relationship, so I also recommend reading my answer on that here.

Upvotes: 1

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