Reputation: 2884
Here`s the question.
public abstract class A {}
public class B:A
{
public TypeF FieldB;
}
public class C:A
{
public TypeG FieldC;
}
public class TypeF:A { }
public class TypeG:A { }
I want to have interface ex: ITypeFG and to implement it in B and C BUT to have properties names FieldB and FieldC
interface ITypeFG
{
public A FieldFG; //But i want to have names TypeF in A and TypeG in B
}
Can this be done? Thanks.
Upvotes: 2
Views: 1118
Reputation: 33930
Sounds like you should treat the field names as data along with A. That way you can keep a common interface and only vary the content of what is returned:
class Data
{
public string Name {get;set;}
public A Value {get;set;}
}
interface ITypeFG
{
Data Field {get;}
}
class B : A, ITypeFG
{
public Data Field
{
get
{
return new Data {Name = "TypeF", Value = FieldB};
}
}
}
class C : A, ITypeFG
{
public Data Field
{
get
{
return new Data {Name = "TypeG", Value = FieldC};
}
}
}
Upvotes: 0
Reputation: 113452
Two points:
As Marc Gravell suggests, a decent workaround is to use explicit implementations. If the client has a reference to the implementing object typed as the interface, they can use the "general" name of the property. If they have a specific reference (i.e. typed as the implementing type) , they can use the "specific" name (and won't be confused by the general name since they won't see it on IntelliSense, for example).
Upvotes: 3
Reputation: 1063599
explicit interface implementation:
public class B : A, ITypeFG
{
public TypeF FieldB { get; set; } // please don't expose public fields...
A ITypeFG.FieldFG { get { return FieldB; } }
}
public class C : A, ITypeFG
{
public TypeG FieldC { get; set; }
A ITypeFG.FieldFG { get { return FieldC; } }
}
Note that if the interface has a setter, you'll need to cast:
public class B : A, ITypeFG
{
public TypeF FieldB { get; set; }
A ITypeFG.FieldFG { get { return FieldB; } set { FieldB = (TypeF)value; } }
}
public class C : A, ITypeFG
{
public TypeG FieldC { get; set; }
A ITypeFG.FieldFG { get { return FieldC; } set { FieldC = (TypeG)value; } }
}
Upvotes: 5