CODEWITHSUNDEEP
kotlin
Amita
Amita

Reputation: 315

Open the file chooser in an Android app using Kotlin

Task: Upload an image which the user can choose from the device.

How can I open the file chooser window on a button press in an Android app using Kotlin?

Upvotes: 13

Views: 22977

Answers (2)

Uchoa
Uchoa

Reputation: 11

I am using it in a PDF reader inside of a Fragment.

My code (without defining the correct directory to choose my file):

val selectedFile = data?.data // The URI with the location of the file <p>
pdfView.fromUri(selectedFile).load() // Show the selected file

// Fragment view
override fun onCreateView(inflater: LayoutInflater, container: ViewGroup?,
                          savedInstanceState: Bundle?): View? {

    val intent = Intent()
            .setType("*/*")
            .setAction(Intent.ACTION_GET_CONTENT)

    startActivityForResult(Intent.createChooser(intent, "Select a file"), 111)
    return inflater.inflate(R.layout.fragment_sat, container, false)
}

Upvotes: 0

Derek
Derek

Reputation: 3016

In your activity, add the button click to add an intent:

btnBack.setOnClickListener {

    val intent = Intent()
            .setType("*/*")
            .setAction(Intent.ACTION_GET_CONTENT)

    startActivityForResult(Intent.createChooser(intent, "Select a file"), 111)
}

Set a custom requestCode, I set 111.

Add the onActivityResult in your activity to catch the result:

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    super.onActivityResult(requestCode, resultCode, data)

    if (requestCode == 111 && resultCode == RESULT_OK) {
        val selectedFile = data?.data // The URI with the location of the file
    }
}

Now selectedFile will contain the location of what they selected.

Upvotes: 25

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