Reputation: 23502
I have the following directory structure
.
|_build.sh
|_dir
|_build.sh
|_Dockerfile
Here is the content of upper level build.sh
#!/bin/bash
./dir/build.sh
and here is the content of bottom level build.sh
#!/bin/bash
docker build -t test .
However, when I run upper level build.sh I get the following error
unable to prepare context: unable to evaluate symlinks in Dockerfile path: GetFi
leAttributesEx C:\Dockerfile: The system cannot find the fil
e specified.
How do I preserve the relative path relative to the location of the script being called?
Upvotes: 3
Views: 240
Reputation: 36813
Slightly different approach but might work. This in your top level build.sh:
#!/bin/bash
cd ./dir
docker build -t test .
Upvotes: 1