CODEWITHSUNDEEP
javaunicodeemoji
Chandra Ari Gunawan
Chandra Ari Gunawan

Reputation: 183

How to generate emoji unicode like "\uD83D\uDE02" when i got is "U+1F602"?

I'm currently creating something like emoji-keyboard in Android that will show list of emoticon

I don't want to use image, so I need Unicode character for emoji in Java source code to show emoticon in String output.

For example

Unicode Name: FACE WITH TEARS OF JOY šŸ˜‚
C/C++/Java source code: "\uD83D\uDE02"
http://www.fileformat.info/info/unicode/char/1f602/index.htm

I need Java Unicode like this "\uD83D\uDE02" because when I output Label with

Label.setText("\uD83D\uDE02");`

it works and shows FACE WITH TEARS OF JOY šŸ˜‚

I've already googled this and found this list, I just don't understand how \uD83D\uDE02 was generated.

Upvotes: 3

Views: 20626

Answers (2)

Basil Bourque
Basil Bourque

Reputation: 340138

"šŸ˜‚"

Java source code supports all 149,813ā€  Unicode characters directly. No need to escape.

String x = "šŸ˜‚" ;
System.out.println ( "x = " + x );

See this code run at Ideone.com.

x = šŸ˜‚

Unfortunately, as of 2024, some IDEs such as IntelliJ are buggy in their lack of support for pasting some characters. This is purely a flaw in the IDE, not a problem with Java nor the javac compiler. My workaround: Paste the problematic character(s) as a Comment in the code-editor, then select and drag into the line of code.

Hex

Your 1F602 input is a hexadecimal number, equivalent to 128,514 in decimal.

You can use that hex number as a numeric literal in Java. Prefix with 0x to distinguish from decimal literal.

int codePointHex = 0x1F602;
String x = Character.toString ( codePointHex );
System.out.println ( "x = " + x );

x = šŸ˜‚

Decimal

You can use the decimal number as a literal, rather than hex. Same result.

int codePointHex = 128_514;
String x = Character.toString ( codePointHex );
System.out.println ( "x = " + x );

x = šŸ˜‚

Avoid char

Beware: The char type has been essentially broken since Java 2, and legacy since Java 5. As a 16-bit value, char is physically incapable of representing most characters. Methods such as String#length can return unuseful results.

System.out.println ( "šŸ˜‚".length ( ) );  // Not useful.

2

Instead, use Unicode code point integer numbers to work with individual characters.

System.out.println ( "šŸ˜‚".codePoints ( ).count ( ) );

1

See the code point numbers.

"šŸ˜‚".codePoints ().forEach ( System.out :: println );

128514

Properties

You can ask about a character, via its code point number.

Character.isEmoji ( 128_514 )  // Or pass 0x1F602.

true

Character.getName ( 0x1F602 )  // Or pass 128_514.

FACE WITH TEARS OF JOY

ā€ Java 22 & Java 23 support Unicode 15.1 which defines 149,813 characters. Unicode 16.0 defines 154,998 characters.

Upvotes: 0

Ferrybig
Ferrybig

Reputation: 18834

U+1F602 is an Unicode codepoint. Java can read these.

System.out.println(new StringBuilder().appendCodePoint(0x1F602).toString());

If you really need to convert it to the other kind of Unicode scapes, you can iterate through all the chars, and write those hex codes to the output:

for(char c : new StringBuilder().appendCodePoint(0x1F602).toString().toCharArray()) {
    System.out.print("\\u" + String.valueOf(Integer.toHexString(c)));
}
System.out.println();

Upvotes: 3

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