CODEWITHSUNDEEP
javascriptjquery
Chi Lee
Chi Lee

Reputation: 35

Javascript IF statement not returning as expected

I'm trying to write a simple javascript code to generate a random door (either door1 or door2, and if door1 is generated, the phrase 'you win' appears.

Right now, despite if door1 or door2 is generated, the output is still 'you lose'. What am I doing wrong?

let doors = ["door1", "door2"]

function selectDoor() {
    const randomDoor = doors[Math.round(Math.random())]
    console.log(randomDoor)
}

if(selectDoor() === "door1") {
    console.log('you win')
} else {
    console.log('you lose')
}

Upvotes: 0

Views: 39

Answers (2)

John Wink
John Wink

Reputation: 295

You should return the value in the function

let doors = ["door1", "door2"]

function selectDoor(){
const randomDoor = doors[Math.round(Math.random())]
console.log(randomDoor);
return randomDoor;
}


if(selectDoor() === "door1"){
    console.log('you win')
} else {
    console.log('you lose')
}

Upvotes: 1

Joseph
Joseph

Reputation: 119827

You're not returning randomDoor from selectDoor.

function selectDoor(){
  const randomDoor = doors[Math.round(Math.random())]
  console.log(randomDoor)
  return randomDoor
}

Returning nothing is equivalent to returning undefined which is a falsy value, effectively a false when used with comparison operators.

Upvotes: 1

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