Reputation: 621
I am still new to swift and i am trying to fetch json data and pass it to the next view as an object which i created. However, i am getting this error Cannot convert value of type 'Dictionary?' to expected argument type 'Data' when i try to user the decoder class. I am not sure what to do to fix it. I have tried changing Dictionary?' to Data in my completion handler but i am still getting errors.
This is my code :
Service call
class ServiceCall: NSObject, ServiceCallProtocol, URLSessionDelegate {
let urlServiceCall: String?
let country: String?
let phone: String?
var search: SearchResultObj?
init(urlServiceCall: String,country: String, phone: String){
self.urlServiceCall = urlServiceCall
self.country = country
self.phone = phone
}
func fetchJson(request: URLRequest, customerCountry: String, mobileNumber: String, completion: ((Bool, Dictionary<String, Any>?) -> Void)?){
let searchParamas = CustomerSearch.init(country: customerCountry, phoneNumber: mobileNumber)
var request = request
request.httpMethod = "POST"
request.httpBody = try? searchParamas.jsonData()
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
let session = URLSession.shared
let task = session.dataTask(with: request, completionHandler: { data, response, error -> Void in
do {
let json = try JSONSerialization.jsonObject(with: data!) as! Dictionary<String, Any>
let status = json["status"] as? Bool
if status == true {
print(json)
}else{
print(" Terrible failure")
}
} catch {
print("Unable to make an api call")
}
})
task.resume()
}
}
SearchViewModel
func searchDataRequested(_ apiUrl: String,_ country: String,_ phone:String) {
let service = ServiceCall(urlServiceCall: apiUrl, country: country, phone: phone)
let url = URL(string: apiUrl)
let request = URLRequest(url: url!)
let country = country
let phone = phone
service.fetchJson(request: request, customerCountry: country, mobileNumber: phone)
{ (ok, json) in
print("CallBack response : \(String(describing: json))")
let decoder = JSONDecoder()
let result = decoder.decode(SearchResultObj.self, from: json)
print(result.name)
// self.jsonMappingToSearch(json as AnyObject)
}
}
New error:
Upvotes: 1
Views: 13015
Reputation: 285082
You are going to deserialize the JSON twice which cannot work.
Instead of returning a Dictionary
return Data
, this mistake causes the error, but there are more issues.
func fetchJson(request: URLRequest, customerCountry: String, mobileNumber: String, completion: (Bool, Data?) -> Void) { ...
Then change the data task to
let task = session.dataTask(with: request, completionHandler: { data, response, error -> Void in
if let error = error {
print("Unable to make an api call", error)
completion(false, nil)
return
}
completion(true, data)
})
and the service call
service.fetchJson(request: request, customerCountry: country, mobileNumber: phone) { (ok, data) in
if ok {
print("CallBack response :", String(data: data!, encoding: .utf8))
do {
let result = try JSONDecoder().decode(SearchResultObj.self, from: data!)
print(result.name)
// self.jsonMappingToSearch(json as AnyObject)
} catch { print(error) }
}
}
And you have to adopt Decodable
in ServiceCall
class ServiceCall: NSObject, ServiceCallProtocol, URLSessionDelegate, Decodable { ...
Further I highly recommended to separate the class model from the code to retrieve the data.
Upvotes: 3
Reputation: 100503
The data returned from session's task can either be serialized with JSONSerialization
or decode it with JSONDecoder
let task = session.dataTask(with: request, completionHandler: { data, response, error -> Void in
either
let json = try JSONSerialization.jsonObject(with: data!) as! Dictionary<String, Any>
OR
let result = try decoder.decode([item].self,data!)
the second argument of the decode method expects a parameter of type Data
not Dictionary
you have to only edit the completion of fetchJson
to return Bool,Data instead of Bool,Dictionary,and remove JSONSerialization
code from it
Upvotes: 2