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vb.netnumbersintegerdivision
pimvdb
pimvdb

Reputation: 154928

Fast way to check if a number is evenly divisible by another?

I was wondering what the fastest way is to check for divisibility in VB.NET.

I tried the following two functions, but I feel as if there are more efficient techniques.

Function isDivisible(x As Integer, d As Integer) As Boolean
     Return Math.floor(x / d) = x / d
End Function

Another one I came up with:

Function isDivisible(x As Integer, d As Integer) As Boolean
     Dim v = x / d
     Dim w As Integer = v
     Return v = w
End Function

Is this a more practical way?

Upvotes: 8

Views: 51790

Answers (3)

gor
gor

Reputation: 11658

Use Mod:

Function isDivisible(x As Integer, d As Integer) As Boolean
    Return (x Mod d) = 0
End Function

Upvotes: 36

kefeizhou
kefeizhou

Reputation: 6552

use the mod operator

Upvotes: 4

Matt F
Matt F

Reputation: 595

Use 'Mod' which returns the remainder of number1 divided by number2. So if remainder is zero then number1 is divisible by number2.

e.g.

Dim result As Integer = 10 Mod 5 ' result = 0

Upvotes: 8

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