CODEWITHSUNDEEP
python
BonBon
BonBon

Reputation: 1

Python NameError: name 'lix' is not defined

dictx1 = {}
dictx2 = {'C':['D','A'],'sXZ':['W','L']}
dictx3 = {'C':['3','4'],'sXZ':['3KL','E','S']}

I want to merge dictx2 and dictx3 to dictx1 and get the output as "{'C': ['D', 'A','3','4'], 'sXZ': ['W', '3KL', 'L', 'E','S']}"

I wrote below code

dictx1 = {}
dictx1 = dictx2.copy()
ds= [dictx1, dictx3]
for i in dictx2.keys():
    dictx1[i] = list(lix[i][x] for x in range(len(lix[i]) for lix in ds)

Error: dictx1[i] = list(lix[i][x] for x in range(len(lix[i])) for lix in ds) NameError: name 'lix' is not defined

But it already there with the 'for lix in ds'. I can write the code as below to get the same answer. But I want to know what's wrong with the above one line for code

s=[]

for i in dictx2.keys():

for li in ds:
    for x in range(len(li[i])):
        s.append(li[i][x])

dictx1[i] = s

s = []

print (dictx1)

Upvotes: 0

Views: 71

Answers (2)

Aran-Fey
Aran-Fey

Reputation: 43196

You can use a defaultdict and add all lists in a loop:

from collections import defaultdict

dictx1 = defaultdict(list)
for dic in (dictx2, dictx3):
    for key, value in dic.items():
        dictx1[key].extend(value)

# result: defaultdict(<class 'list'>, {'C': ['D', 'A', '3', '4'],
#                                      'sXZ': ['W', 'L', '3KL', 'E', 'S']})

If you don't want a defaultdict as the result, add dictx1 = dict(dictx1) to turn it into a normal dict.

Upvotes: 0

shahaf
shahaf

Reputation: 4983

dictx2 = {'C':['D','A'],'sXZ':['W','L']}
dictx3 = {'C':['3','4'],'sXZ':['3KL','E','S']}

for k,v in dictx2.items():
    res =  dictx3.get(k, None)
    if res == None:
        dictx3.update({k:v})
    else:
        dictx3.update({k : v + res})

print(dictx3)

output

{'C': ['D', 'A', '3', '4'], 'sXZ': ['W', 'L', '3KL', 'E', 'S']}

Upvotes: 2

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