Reputation: 11
I know we can use data steps to infile "*.sas" programs as a dataset, each line of code is one record of the dataset. And then I can make changes to the dataset with SAS.
Let's say I have 100 programs already exist in c:\pgm, all I need to do is minor modifications, such as changing flag1 to flag2 for all these 100 program. If I don't want to open each program and substitute the flag one by one. Is there a way to get all program names in c:\pgm, so that I can loop over these names and do the substitution.
I'm using SAS 9.4 and EG. Thanks!
Upvotes: 0
Views: 565
Reputation: 349
I might have overcomplicated it a bit, but the idea is the following:
%let dir=C:\prg;
%let var_prefix=vars_;
%macro batchEdit;
data _null_;
pfad="&dir.";
rc=filename("fileref",pfad);
did=dopen("fileref");
if did eq 0 then do;
putlog "Dir does not exist";
return;
end;
num=dnum(did);
j=1;
do i=1 to dnum(did);
name=dread(did,i);
if UPCASE(substrn(name,max(1,length(name)-3),4)) eq ".SAS" then do;
call symput(CATS("&var_prefix.",j),name);
j=j+1;
end;
end;
call symput("varcnt",j);
rc=dclose(did);
rc=filename("fileref");
run;
%DO j=1 %TO &varcnt.;
%editFile(file=&&&var_prefix&j);
%END;
%mend;
%macro editFile(file=);
%put In this Macro you should define what modification should be done on each single file;
%put Current File: &file.;
%mend;
%batchEdit;
P.S. I have tested it on unix SAS server, so it might require some modifications on PC SAS.
Upvotes: 0