Reputation: 7158
Quality
can be good or bad, depending upon the type. Here type guards are working fine
enum GoodBad {
Good = 'Good',
Bad = 'Bad'
}
interface IQuality {
readonly type: GoodBad;
}
interface GoodQuality extends IQuality {
readonly type: GoodBad.Good;
}
interface BadQuality extends IQuality {
readonly type: GoodBad.Bad;
}
type Quality = GoodQuality | BadQuality;
let quality: Quality;
if (quality.type == GoodBad.Good) {
let goodQuality: GoodQuality = quality; // No Problem. Working good.
let badQuality: BadQuality = quality; // Throw error. Working good.
}
But now when I wrap quality in Product
then
interface IProduct {
readonly quality: Quality;
}
interface GoodProduct extends IProduct {
readonly quality: GoodQuality;
}
interface BadProduct extends IProduct {
readonly quality: BadQuality;
}
type Product = GoodProduct | BadProduct;
let product: Product;
if (product.quality.type == GoodBad.Good) {
let goodProduct: GoodProduct = product; // Throw error. Working Bad.
// let badProduct: BadProduct = product; // Throw error. Working fine.
}
Type guard don't work as intended.
if
block and previous if
block? let goodProduct: GoodProduct = product;
why it is throwing error?readonly type: GoodBad
on IProduct
. But this is extra, can this be eliminated?Upvotes: 3
Views: 4729
Reputation: 249466
The type guard will affect the quality
field, not the product
variable. Type-guards only impact the field that owns the discriminating field; it does not affect the owner.
So this works:
type Product = GoodProduct | BadProduct;
let product!: Product;
if (product.quality.type == GoodBad.Good) {
let goodQuality: GoodQuality = product.quality; // Ok
let badQuality: BadQuality = product.quality; // Err
let goodProduct: GoodProduct = product; // Err, product not affected
let badProduct: BadProduct = product; // Err, product not affected
}
Your solution of adding an extra field is a good one, another would be to create a custom type guard:
function isGoodProduct(p: Product) : p is GoodProduct {
return p.quality.type === GoodBad.Good
}
if (isGoodProduct(product)) {
let goodProduct: GoodProduct = product; // OK
let badProduct: BadProduct = product; // Err
}
Upvotes: 4