CODEWITHSUNDEEP
c
Hosein Shendabadi
Hosein Shendabadi

Reputation: 362

Search a string in an allocated array(c)

I want to find a string in an array stored in a pointer.I already tried this way:

#include <stdio.h>
#include <malloc.h>
#include <stdlib.h>
int main() {
int n,i;
char (*ptr)[50];
char search[50];
printf("How many students?\n");
scanf("%d",&n);
for(i=0;i<n;i++){
    printf("Enter the name of student:\n");
    scanf("%49s", ptr[i]);
}
printf("Enter a name to search:\n");
scanf("%49s",search);
for (i=0;i<n;i++){
    printf(strcmp(ptr[i],search));

}
}

But I see this error:

[Warning] passing argument 1 of 'printf' makes pointer from integer without a cast

Upvotes: 0

Views: 71

Answers (1)

Achal
Achal

Reputation: 11931

Firstly, strcmp returns integer not address(see https://linux.die.net/man/3/strcmp). Replace printf(strcmp(ptr[i],search)); should be printf("%d\n",strcmp(ptr[i],search));

Secondly, char (*ptr)[50]; is pointer to an array, where its pointing ? Its unnecessary, better you can take array of pointer char *ptr[50];

char *ptr[50];/* array of 50 char ptr */
for(i=0;i<n;i++){
      ptr[i] = malloc(size); /* allocate memory for each char buf, define size */
      printf("Enter the name of student:\n");
      scanf("%49s", ptr[i]);
}

And

for (i=0;i<n;i++){
     //printf("%d\n",strcmp(ptr[i],search));
     if(strcmp(ptr[i],search) == 0) {
       printf("%s exists \n",search);
     }
}

Also once job is done don't forget to free the dynamically allocated memory for each array of char pointer by calling free(). Something like this

for(int i =0 ;i < n;i++) {
   free(ptr[i]);
}

Upvotes: 1

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