Reputation: 29
It prints "that wasn't an option" When I press Y or N even though I have it
I have it set as != (not equal to)
if c.upper() != 'N' or "Y":
print ("that wasn't an option")
if c.upper() != 'N' or "Y":
sys.exit()
Whole code
import sys
c = input('do you like piza? Y or N:')
if c.upper() != 'N' or "Y": print ("that wasn't an option")
if c.upper() != 'N' or "Y": sys.exit()
if c.upper() == 'Y':
print ('Me To')
if c.upper() == 'N': print ("really i thought everybody likes piza.")
if c.upper() == 'N': sys.exit()
name = input("sooo what's ur name? ")
print("that a pretty good name i guess ")`
Upvotes: 2
Views: 47
Reputation: 1823
You had made a mistake by just putting the or
statement without specifying a condition. Instead of just or
ing a value, you have to specify another condition. Here I have provided an example how it should be.
import sys
c = input('do you like piza? Y or N:')
if c.upper() != 'N' or c.upper() != "Y":
print ("that wasn't an option")
if c.upper() != 'N' or c.upper() != "Y":
sys.exit()
if c.upper() == 'Y':
print ('Me To')
if c.upper() == 'N':
print ("really i thought everybody likes piza.")
if c.upper() == 'N':
sys.exit()
name = input("sooo what's ur name? ")
print("that a pretty good name i guess ")
You could also slightly refactor the code, by combining the last 2 if
s like so:
if c.upper() == 'N':
print("really i thought everybody likes piza.")
sys.exit()
and also the 1st two if
s like so:
if c.upper() != 'N' or c.upper() != "Y":
print ("that wasn't an option")
sys.ext()
EDIT
The or
should be replaced with an and
, otherwise that check makes no sense.
Credit to khelwood for pointing it out.
Hope this helps!
Upvotes: 2