CODEWITHSUNDEEP
phpjsonajax
Patrick Duke Schauer
Patrick Duke Schauer

Reputation: 91

Ajax - Send PHP value via ajax to another page

i have a form with a switch toggle and a input field named userid. When i switch the toggle all works fine and the active.php save the new status in the database. But now i want to have also the userid value to the active.php. The var mode can i get in the active.php via 

$mode=$_POST['mode'];

How can i send the userid also to active.php?

Any idea? Thank you

 <input type="checkbox" name="<?php echo 'toggle'.$c;?>" id="<?php echo 'toggle'.$c;?>" data-toggle="toggle" data-off="OFF" data-on="ON" checked>

 <input id="userid" name="userid" type="hidden" value="<?php echo $userid;?>">

This is the js code

$('#<?php echo 'toggle'.$c;?>').change(function(){
         var mode= $(this).prop('checked'),
 $.ajax({
      type:'POST',
      dataType:'JSON',
      url:'active.php',
      data:'mode='+mode,
      success:function(data)
      {
        var data=eval(data);
        message=data.message;
        success=data.success;
        $("#heading").html(success);
        $("#body").html(message);

      }
    });
  });

Upvotes: 0

Views: 38

Answers (2)

Daniel Mendes
Daniel Mendes

Reputation: 23

In your ajax parameter, change the data attribute to look as follows:

data: 'mode='+mode + '&userid=' + $('#userid').val ()

Upvotes: 0

Rotimi
Rotimi

Reputation: 4825

Use the & to separate the two keys.

First of all, retrieve the userid value 

var userid = $('#userid').val();

data:'mode=' +mode+'&userid='+userid,

Upvotes: 1

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