Reputation: 11
I'm new to python and currently playing around with argpase. I'm trying to call a function using a directory path given as a command line argument followed by an argparse option(-name) and a regex that goes through all the files in the directory and spits out all the matches to the regex as so:
./find.py ../seek -name '[a-z]*\.txt'
However, I'm getting a error that looks like
usage: find.py [-h] [--path PATH] [-name] [--regex REGEX]
find.py: error: unrecognized arguments: . . / s e e k / p r o g r a m . c
And without the -name its just printing all the files inside the path.
Here is what I have so far:
#!/usr/bin/python2.7
import os, sys, argparse,re
from stat import *
def parse(argv=None):
parser = argparse.ArgumentParser()
parser.add_argument('--path', help='path of directory', action='store')
parser.add_argument('-name', '--name', action='store_true')
parser.add_argument('--regex', default=r"[a-z0-9A-Z]")
args = parser.parse_args(argv)
print(args)
return args
def main(argv=None):
direc = sys.argv[1]
files = []
for f in os.listdir(direc):
pathname = os.path.join(direc, f)
mode = os.stat(pathname).st_mode
if S_ISREG(mode):
args = parse(pathname)
if args.name:
dirls = [re.match(args.regex, pathname)]
print(dirls)
else:
print pathname
if __name__ == '__main__':main()
Any thoughts?
Upvotes: 0
Views: 785
Reputation: 1465
Argument Parser PATH Example : Different type of arguments with custom handlers added. For path here you can pass '-path' followed by path value as argument
import os
import argparse
from datetime import datetime
def parse_arguments():
parser = argparse.ArgumentParser(description='Process command line arguments.')
parser.add_argument('-path', type=dir_path)
parser.add_argument('-e', '--yearly', nargs = '*', help='yearly date', type=date_year)
parser.add_argument('-a', '--monthly', nargs = '*',help='monthly date', type=date_month)
return parser.parse_args()
def dir_path(path):
if os.path.isdir(path):
return path
else:
raise argparse.ArgumentTypeError(f"readable_dir:{path} is not a valid path")
def date_year(date):
if not date:
return
try:
return datetime.strptime(date, '%Y')
except ValueError:
raise argparse.ArgumentTypeError(f"Given Date({date}) not valid")
def date_month(date):
if not date:
return
try:
return datetime.strptime(date, '%Y/%m')
except ValueError:
raise argparse.ArgumentTypeError(f"Given Date({date}) not valid")
def main():
parsed_args = parse_arguments()
if __name__ == "__main__":
main()
Upvotes: 1
Reputation: 5207
In order for your program to operate, you need a path. So, the --path
option must take an argument. Modify your parse()
function to change the line
parser.add_argument('--path', help='path of directory', action='store')
to
parser.add_argument('--path', help='path of directory', action='store', required=True)
You need to call parse_args()
only once. Remove the parse()
invocation to the top of the loop.
And you needn't do
direc = sys.argv[1]
if you are using argparse
.
re.match()
returns a match
object, which is probably not what you want to print.
You might want to take a look at match()
versus search()
.
The
match()
function only checks if the RE matches at the beginning of the string whilesearch()
will scan forward through the string for a match.
If you wanted to print the file names matching the regex, you could do
if S_ISREG(mode):
#args = parse(pathname)
if args.name:
#dirls = re.match(args.regex, pathname)
dirls = re.search(args.regex, pathname)
if( dirls ):
print(pathname)
else:
print pathname
So main()
should be something like
def main(argv=None):
args = parse(sys.argv[1:])
print(args)
#direc = sys.argv[1]
direc = args.path
files = []
for f in os.listdir(direc):
pathname = os.path.join(direc, f)
mode = os.stat(pathname).st_mode
if S_ISREG(mode):
#args = parse(pathname)
if args.name:
#dirls = re.match(args.regex, pathname)
dirls = re.search(args.regex, pathname)
if( dirls ):
print(pathname)
else:
print pathname
In order to specify the regex matching the file names, you must specify the regex using the --regex
option. By default, you've made it to match names having only numbers and (English) letters.
./find.py --path ../seek -name --regex [a-z]\*.txt
or
./find.py --path ../seek -name --regex '[a-z]*.txt'
Upvotes: 0