CODEWITHSUNDEEP
php
Nikk
Nikk

Reputation: 7901

Alternative to number_format() that will erase `.00` but will leave `.5` or `.567`

I have numbers that look like this:

    175.0000
    185.0000
    195.0000
    205.0000
    13.0000
    15.0000

But I also have numbers that look like this:

    10.5000
    7.5000

The function number_format() is not cutting it because, if I set it to leave 1 decimal place, it will leave the .0 in the numbers that aren't 7.5 or 10.5.

Is there a function that will only display a decimal point if it is greater than 0?

Upvotes: 0

Views: 1827

Answers (5)

Omar Abu Omar
Omar Abu Omar

Reputation: 60

try this:

$arr=[175.0000, 185.0000, 195.0000, 205.0000, 13.0000, 15.0000, 10.5000, 7.5000 ];
foreach ($arr as $value) {
    echo round($value,2)."\n";
}

This will work for sure!

Upvotes: 1

Denis Rudenko
Denis Rudenko

Reputation: 11

Try this 

$a =  Array("13.0000",
            "15.0000",
            "10.5000",
            "7.5000");

$a = preg_replace('/0+$/', "", $a);
$a = preg_replace('/[.]$/', "", $a);

Result = 13, 15, 10.5, 7.5

Upvotes: 1

Syscall
Syscall

Reputation: 19764

You can compare the number with its integer value to check the number of decimal you need:

$num = 7.0;
echo number_format($num, ($num == (int)$num) ? 0 : 1);
$num = 7.5;
echo number_format($num, ($num == (int)$num) ? 0 : 1);

Output:

7
7.5

A shorter version only if you need 1 decimal:

echo number_format($num, $num != (int)$num); // bool to int = 0 or 1.

Another way is to use rtrim() twice: first for zéros, second for dot:

echo rtrim(rtrim(number_format($num, 3), '0'),'.');

Upvotes: 1

yabberth
yabberth

Reputation: 505

I'm not very experienced with php but I found this

echo 13.00 + 0; //gives you 13
echo '125.00' + 0; //gives you 125
echo 76.5 + 0; //gives you 76.5

PHP Type Juggling

Upvotes: 1

Adi219
Adi219

Reputation: 4814

This isn't in PHP, but is the general algorithm.

There are several ways to do this:

if unformattedNumber % 1 == unformattedNumber:
    formattedNumber = number_format(unformattedNumber)
else:
    formattedNumber = number_format(unformattedNumber, 1)

or

formattedNumber = number_format(unformattedNumber, 1)
if formattedNumber[-1] == 0:
    formattedNumber = number_format(formattedNumber)

Upvotes: 0

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