CODEWITHSUNDEEP
mathluareverse-engineering
Hgs Ca
Hgs Ca

Reputation: 51

How would I implement this inverse exponential in lua?

11 -> 3
10 -> 3.1
9 -> 3.333
8 -> 3.5
7 -> 3.7142857142857
6 -> 4
5 -> 4.4
4 -> 5
3 -> 5.666
2 -> 7
1 -> 10

Basically I'm trying to reverse engineer a function for calculating Xp awarded to a player. The first number is what you feed into the function, while the second number is what it returns. After visualizing the returned numbers I figured out that they're an inverse exponential, but I've had no luck in implementing them in lua.

Upvotes: 0

Views: 484

Answers (1)

Egor Skriptunoff
Egor Skriptunoff

Reputation: 23757

for n = 1, 11 do
   local xp = math.floor(10 * n^.5)/n
   print(n, xp)
end

Output:

1   10
2   7
3   5.6666666666667
4   5
5   4.4
6   4
7   3.7142857142857
8   3.5
9   3.3333333333333
10  3.1
11  3

Upvotes: 4

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