CODEWITHSUNDEEP
vim
Frido Emans
Frido Emans

Reputation: 5588

mulitply numbers in text by a constant using vim

I have this piece of text:

(-1.000mm 1.000mm)
(-0.500mm 0.800mm)
(0.500mm 1.200mm)

(1.000mm 1.000mm)
(0.800mm 0.500mm)
(1.200mm -0.500mm)

(1.000mm -1.000mm)
(0.500mm -0.800mm)
(-0.500mm -1.200mm)

(-1.000mm -1.000mm)
(-0.800mm -0.500mm)
(-1.200mm 0.500mm)

(-1.000mm 1.000mm)

I would like to multiply all of these numbers by 0.95 (and other numbers). What I tried is:

:%s/[0-9.]*mm/\=submatch(0)*0.95/g

but the result is:

(-0.95 0.95)
(-0.0 0.0)
(0.0 0.95)

(0.95 0.95)
(0.0 0.0)
(0.95 -0.0)

(0.95 -0.95)
(0.0 -0.0)
(-0.0 -0.95)

(-0.95 -0.95)
(-0.0 -0.0)
(-0.95 0.0)

(-0.95 0.95)

I must be doing something wrong with the grouping or something because besides most numbers turning to 0.0, the mm falls away.

Upvotes: 2

Views: 244

Answers (1)

L3viathan
L3viathan

Reputation: 27283

The problem is that your floaty strings are coerced to integers during multiplication, not floats. The second issue is that you replace the mm:

:%s/[0-9.]*\zemm/\=str2float(submatch(0))*0.95/g

The str2float function turns a string into a float. The \ze regex special sequence "matches at any position, and sets the end of the match there."

Result:

(-0.95mm 0.95mm)
(-0.475mm 0.76mm)
(0.475mm 1.14mm)

(0.95mm 0.95mm)
(0.76mm 0.475mm)
(1.14mm -0.475mm)

(0.95mm -0.95mm)
(0.475mm -0.76mm)
(-0.475mm -1.14mm)

(-0.95mm -0.95mm)
(-0.76mm -0.475mm)
(-1.14mm 0.475mm)

(-0.95mm 0.95mm)

Upvotes: 5

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