CODEWITHSUNDEEP
c#vbabitwise-operatorsbit-shift
Sam King
Sam King

Reputation: 85

Convert VBA bitwise operator to C#

I have a bitwise operations in VBA and now I want to convert that to C#.

I tried converting using the C# bitwise operators but I didn't get the result.

VBA Bitwise Operations

Bit1 = (Var1 And 2 ^ 14) Or (Var1 And 2 ^ 15)

C# Bitwise Operations

var Bit1 = (bitvalue >> 14) | (bitvalue >> 15);

Since VBA doesn't have bit shift operators we use 2^places for right shift and in C# we can simply use >> for right shift operator, but it's not giving me the result which I am getting it in VBA. What could be the reason?

This is my full C# function and it's similar in VBA:

public void bitcalc()
{


    var Bit1 = (bitvalue >> 14) | (bitvalue >> 15);
    if (Bit1 == 16384) getISO15031BitsLetter = "C";

    else if (Bit1 == 32768) getISO15031BitsLetter = "B";


    else if (Bit1 == 49152) getISO15031BitsLetter = "U";


    else getISO15031BitsLetter = "P" ;


}

Upvotes: 0

Views: 154

Answers (1)

Nico Schertler
Nico Schertler

Reputation: 32627

Your original code does not shift the input. It only masks it. A direct translation could be:

var Bit1 = (Var1 & (1 << 14)) | (Var1 & (1 << 15));

There are multiple variations to this. E.g., you could mask both bits at the same time:

var Bit1 = (Var1 & (3 << 14)); // decimal 3 is binary 11

Upvotes: 2

Related Questions