CODEWITHSUNDEEP
php
tobyku
tobyku

Reputation: 45

How to export array from php file to another php file

In one file i have something like this:

    $result = mysqli_query($con, "SELECT * FROM users WHERE id_province = '".$province_id."' AND id_city = '".$city_id."' AND age >= '".$age1."' AND
    age <= '".$age2."' AND id_rank = '".$rank_id."' AND id_position = '".$position_id."';");

    while ($row = mysql_fetch_array($result)) {
        $array[] = $row;
    }

And I want to use $array in another file. How can I do it?

Upvotes: 4

Views: 1935

Answers (4)

anon
anon

Reputation:

So... "export" is the wrong term for this, what you are looking at is variable scope

In the simplest terms - something declared outside a function is "global" and something declared within a function is private to that

You want to pass an array from one file to another? If you have 3 files (main, include_num1 and include_num2), this is simple;

Main;

<?php
require_once 'include_num1.php';
require_once 'include_num2.php';
?>

include_num1;

<?php
$myarray = array("a", "b", "c")
?>

include_num2;

<?php
var_dump($myarray);
?>

This will produce something like;

myarray = (array)
    string 0 : a(1)
    string 1 : b(1)
    string 2 : c(1)

This is because in this example, the array is declared in the global scope, if you did the require's the other way around - this would error as at time of the var dump, $myarray does not exist

You can skip out the "main" by just including the include_num2 from the include_num1

If you want to use a global variable inside a function, declare the function as normal, and use the global available;

<?php
$myvar = "A variable";

function myFunction()
{
    if (isset($myvar)) print $myvar; // Will do nothing
    global $myvar;
    if (isset($myvar)) print $myvar; // Will Print "A variable"
}
?>

Upvotes: 1

Davit Huroyan
Davit Huroyan

Reputation: 302

You can use SESSIONS

session_start();    
$result = mysqli_query($con, "SELECT * FROM users WHERE id_province = '" . $province_id . "' AND id_city = '" . $city_id . "' AND age >= '" . $age1 . "' AND
            age <= '" . $age2 . "' AND id_rank = '" . $rank_id . "' AND id_position = '" . $position_id . "';");

while ($row = mysql_fetch_array($result)) {
    $array[] = $row;
}
$_SESSION['array'] = $array;

and in second file you can use code below

@session_start();
$array = $_SESSION['array'];

Upvotes: 4

parker_codes
parker_codes

Reputation: 3397

When trying to pass between multiple files, you could use classes instead of scripts. This helps maintain the code better.

Let's say the second file was SecondFile.class. I could instantiate it and then pass the array as a parameter. 

$secondFile = new SecondFile;
$secondFile->someClassMethod($array);

Or, if you don't need to use the second file for anything else, use a shorter syntax:

(new SecondFile)->someClassMethod($array);

Upvotes: 1

Raphael M.
Raphael M.

Reputation: 140

You can save your array in the database, file, cookie, session....

It depends of what you want to do versus the necessary security level.

The simplest way would be:

//At the top of your page
@session_start();

//This line goes after you get all data you want inside your array
$_SESSION['mySession'] = $array;

And in the other page:

//At the top of your page
@session_start();

//To recover you array:
$array = $_SESSION['mySession'];

Not the best option, but it works.

Upvotes: 0

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