CODEWITHSUNDEEP
javascriptfunction
Niki45nk
Niki45nk

Reputation: 17

Why does my code put out an "maximum call stack size exceeded" error?

I wrote a simple program for learning purposes recently that (for now) basically just adds all the numbers together. But, for some reason, when I try to call it ( the programm is a function ), it puts out an "maximum call stack size exceeded" error. Is there any way to fix it? The answer may be very obvious, but I'm a very beginner at this stuff. Here's the code:

var add = function(num1, num2, num3, num4, num5) {
    for(i = 0; i < add.length; i++) {
if(i === 0) {
var first = add(i);
} else if(i === 1) {
var second = add(i);
} else if(i === 2) {
var third = add(i);
} else if(i === 3) {
var fourth = add(i);
} else if(i === 4) {
var fifth = add(i);
console.log(first + second + third + fourth + fifth);
};
    };
};

add(1, 2, 3, 4, 5);

Upvotes: 1

Views: 58

Answers (1)

Vishnu Kyatannawar
Vishnu Kyatannawar

Reputation: 353

I believe you are learning about arguments.

Since doing a add.length does not make any sense at all.

var add = function(num1, num2, num3, num4, num5) {
  for (i = 0; i < arguments.length; i++) {
    if (i === 0) {
      var first = arguments[i];
    } else if (i === 1) {
      var second = arguments[i];
    } else if (i === 2) {
      var third = arguments[i];
    } else if (i === 3) {
      var fourth = arguments[i];
    } else if (i === 4) {
      var fifth = arguments[i];
    }    
  }
  console.log(first + second + third + fourth + fifth);
};

add(1, 2, 3, 4, 5);

You can write it like this

var add = function() {
  var sum = 0;
  for (var i = 0; i < arguments.length; i++) {
    sum += arguments[i];    
  }
  return sum;
};

console.log(add(1, 2, 3, 4, 5));
console.log(add(1, 2, 3, 4));

Functions are supposed to take arguments, process and then return the result.

Upvotes: 1

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