CODEWITHSUNDEEP
c++printfcout
MandyLB
MandyLB

Reputation: 317

Changing a printf to a cout statement

I'm trying to change a printf statement into an std::cout statement. How would I go about doing that for the following:

printf("\n %.2f Celsius = %.2f Fahrenheit", celsius, fahrenheit);

celcius and fahrenheit are both of float type, and %f comes from scanf("%f", &fahrenheit);.

Upvotes: 1

Views: 344

Answers (1)

Azeem
Azeem

Reputation: 14637

You can use stream manipulators std::fixed and std::setprecision from <iomanip> header to achieve this.

Here's an example:

#include <iostream>
#include <iomanip>

// printf("\n %.2f Celsius = %.2f Fahrenheit", celsius, fahrenheit);

int main()
{
    const float celsius = 10.555;
    const float fahrenheit = 50.999;

    std::cout << '\n'
              << std::fixed
              << std::setprecision( 2 )
              << celsius << " Celsius = "
              << fahrenheit << " Fahrenheit";

    return 0;
}

Output:

10.56 Celsius = 51.00 Fahrenheit

Here's the live example: https://ideone.com/ElJ0Wg

But, this is not as compact as it is with printf. However, there's this formatting library (fmt) that tries to achieve the compactness of printf along with other good stuff. And, AFAIK, it has been proposed to be included in the C++ standard library. So, IMO, it would be a good idea to explore and use it in your projects.

Upvotes: 5

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