Reputation: 23
I'm new to C and have been trying to tackle this question. It's a continuation of the last thread I made. I made some progress but still have so much to learn and fix.
In short:
In this question a "vector" is a one dimensional array of integers. Therefore an array of vectors would be a two dimensional array that holds one dimensional arrays inside him.
I need to use these variables:
I need to write the following functions:
int init(int ***vectors, int **sizes, int size)
the function allocated memory to **vectors and *sizes with size and initializes vectors to be full of NULLs,and sizes to be full of zeros.
int set(int **vectors, int *sizes, int index, int *tmp, int tmp_size)
the function receives an array of nulls (**vectors)), frees the vector inside **vectors whose index is index and allocates memory for a new vector, whose length is tmp_size and places inside it *tmp's elements.
This is my code:
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
int init(int*** vectors, int** sizes, int size)
{
int i, k,j;
*sizes = (int*)malloc(size * sizeof(int));
if (*sizes == NULL)
return 0;
for (j = 0; j < size; j++)
{
(*sizes)[j] = 0;
}
*vectors = (int**)malloc(size * sizeof(int*));
if (*vectors == NULL)
return 0;
for (i = 0; i < size; i++)
{
(vectors)[i] = NULL;
}
return 1;
}
int set(int **vectors, int *sizes, int index, int *tmp, int tmp_size)
{
if ((vectors)[index] != NULL)
{
free((vectors)[index]);
}
(vectors)[index] = (int*)malloc(tmp_size * sizeof(int));
if ((vectors)[index] == NULL)
return 0;
for (int b = 0; b < tmp_size; b++)
{
(vectors)[index][b] = tmp[b];
}
sizes[index] = tmp_size;
return 1;
}
int main()
{
int size, i, length, indexhere;
int** vectors = NULL;
int* sizes = NULL;
int* tmp = NULL;
int* p = &vectors;
int tempindex;
printf("\nPlease enter an amount of vectors:\n");
scanf("%d", &size);
init(p, &sizes, size);
printf("Enter index\n");
scanf("%d", &indexhere);
printf("Enter Length\n");
scanf("%d", &length);
tmp = (int*)malloc(length * sizeof(int));
printf("Enter elements:\n");
for (int g = 0; g < length; g++)
scanf("%d", &tmp[g]);
set(&vectors, sizes, indexhere, tmp, length);
system("pause");
return 0;
}
Could someone explain please why the program always crashes?
Upvotes: 0
Views: 2160
Reputation: 571
Here is a complete working example.
#include <stdio.h>
#include <stdlib.h>
void destroyVectors(int **vectors, int size)
{
for (int i = 0; i < size; i++)
{
free(vectors[i]);
}
}
int init(int*** vectors, int** sizes, int size)
{
int i, j;
*sizes = (int*)malloc(size * sizeof(int));
if (*sizes == NULL)
return 0;
for (j = 0; j < size; j++)
{
(*sizes)[j] = 0;
}
*vectors = (int**)malloc(size * sizeof(int*));
if (*vectors == NULL)
return 0;
for (i = 0; i < size; i++)
{
(*vectors)[i] = NULL;
}
return 1;
}
int set(int **vectors, int *sizes, int index, int *tmp, int tmp_size)
{
if ((vectors)[index] != NULL)
{
free((vectors)[index]);
}
(vectors)[index] = (int*)malloc(tmp_size * sizeof(int));
if ((vectors)[index] == NULL)
return 0;
for (int b = 0; b < tmp_size; b++)
{
(vectors)[index][b] = tmp[b];
}
sizes[index] = tmp_size;
return 1;
}
int main()
{
int size = 0, length = 0, indexhere = 0;
int** vectors = NULL;
int* sizes = NULL;
int* tmp = NULL;
printf("\nPlease enter an amount of vectors:\n");
scanf("%d", &size);
init(&vectors, &sizes, size);
printf("Enter index\n");
scanf("%d", &indexhere);
printf("Enter Length\n");
scanf("%d", &length);
tmp = (int*)malloc(length * sizeof(int));
printf("Enter elements:\n");
for (int g = 0; g < length; g++)
scanf("%d", &tmp[g]);
set(vectors, sizes, indexhere, tmp, length);
for(int i = 0; i < length; ++i)
printf("byte: %d\n", vectors[indexhere][i]);
printf("sizes index: %d\n", sizes[indexhere]);
free(tmp);
free(sizes);
destroyVectors(vectors, size);
return 0;
}
Upvotes: 1
Reputation: 6144
init
function (vectors)[i] = NULL;
should actually be (*vectors)[i] = NULL;
set
function from main
you should pass vectors
instead of &vectors
.There also seems to be several pointer type mismatches in your code, so you should really pay attention to compiler's warnings. This is because C unfortunately allows implicit conversions between incompatible pointers, unlike C++ for example.
Upvotes: 2
Reputation: 409136
You call set
like this
set(&vectors, sizes, indexhere, tmp, length);
but the first argument is declared as an int **
. By passing &vector
you're passing a pointer to vector
, i.e. something of type int ***
. This mismatch will lead to undefined behavior and probable crashes.
Upvotes: 1