CODEWITHSUNDEEP
javascriptecmascript-6safari9
Crashy
Crashy

Reputation: 345

Syntax error unexpected token '>'

I've been testing my JS code on different browsers but it doesn't seem to work on some of them and on mobile either.

JS

function req1() {
  fetch('https://jsonplaceholder.typicode.com/posts/1')
    .then(response => response.json())
    .then(json => {
      var title = json.title;
      var body = json.body; 
      document.getElementById("newsTitle").innerHTML = title;
      document.getElementById("newsContent").innerHTML = body;
      document.getElementById("newsContent2").innerHTML = body;
    });
}
req1();

By reading this question I understood that the problem could be related to '=>' because it is a ES6 element and not all the browsers support it. But as you can see here it seems to be the way to get those json data: https://jsonplaceholder.typicode.com/

Is there a way to avoid using '=>' in this function to make it work on all the browsers?

Here the error that I get on Safari 9 for example:

enter image description here

I tried some solutions but now I get this error:

enter image description here

posts are not printed yet, any idea?

Upvotes: 1

Views: 207

Answers (5)

patelarpan
patelarpan

Reputation: 7991

you need use fetch polyfill and old function syntax not the new arrow function syntax of es6.

function req1() {
  fetch('https://jsonplaceholder.typicode.com/posts/1')
    .then(function (res) {return res.json()})
    .then(function (json) {
      var title = json.title;
      var body = json.body; 
      document.getElementById("newsTitle").innerHTML = title;
      document.getElementById("newsContent").innerHTML = body;
    });
}
req1();
<script src="https://cdnjs.cloudflare.com/ajax/libs/fetch/2.0.4/fetch.js"></script>
<div id="newsTitle"></div>
<div id="newsContent"> </div>

Browser Support For Fetch API polyfill

  • Chrome
  • Firefox
  • Safari 6.1+
  • Internet Explorer 10+

Upvotes: 1

Mamun
Mamun

Reputation: 68933

Change the following lines

then(response => response.json())

To

.then(function(response){ response.json() })

And

.then(json => {

To

.then(function (json) {

Full Code:

function req1() {
  fetch('https://jsonplaceholder.typicode.com/posts/1')
   .then(function(response){ response.json()})
   .then(function (json){
     var title = json.title;
     var body = json.body; 
     document.getElementById("newsTitle").innerHTML = title;
     document.getElementById("newsContent").innerHTML = body;
     document.getElementById("newsContent2").innerHTML = body;
   });
}
req1();

Upvotes: 0

Luca Kiebel
Luca Kiebel

Reputation: 10096

Just use normal function syntax instead of ES6 arrow-syntax:

function req1() {
  fetch('https://jsonplaceholder.typicode.com/posts/1')
    .then(function (res) {return res.json()})
    .then(function (json) {
      var title = json.title;
      var body = json.body; 
      document.getElementById("newsTitle").innerHTML = title;
      document.getElementById("newsContent").innerHTML = body;
      document.getElementById("newsContent2").innerHTML = body;
    });
}
req1();

Most browsers that don't support ES6 arrow-syntax are unlikely to support the Fetch API. For those I would suggest using another form of HTTP request, or using a Polyfill, like GitHub's

Upvotes: 2

Franck
Franck

Reputation: 2499

Why not to use a simple request

 var xhReq = new XMLHttpRequest();
 xhReq.open("GET", "https://jsonplaceholder.typicode.com/posts/1", false);
 xhReq.send(null);
 var serverResponse = xhReq.responseText;
 var json = JSON.parse(serverResponse);
 alert(json.title);

Upvotes: -1

NullDev
NullDev

Reputation: 7303

Use a normal function instead of a lambda:

"use strict";

function req1() {
    fetch('https://jsonplaceholder.typicode.com/posts/1').then(function(response){
        return response.json();
    }).then(function(json){
        var title = json.title;
        var body = json.body;
        document.getElementById("newsTitle").innerHTML = title;
        document.getElementById("newsContent").innerHTML = body;
        document.getElementById("newsContent2").innerHTML = body;
    });
}
req1();

Just write 

.then(function(json){

Instead of

.then(response => response.json())

Also, if you're not sure about the ES6 Syntax in your script, you can use something like babel:

https://babeljs.io/repl/

Upvotes: 1

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