CODEWITHSUNDEEP
bashsed
ganthdev
ganthdev

Reputation: 55

Delete last semicolon of matched line

I have a file with multiple lines. Something like this:

Session
PKG_TEST
Call: command(parameter);
Error: error message
end of log;
Session2
PKG_TEST2
Call: command2(parameter2);
Error: error message
end of log;

I need to remove the semicolon at the end of each line that starts with Call.

I know how to find every line that starts with Call with /^Call.*/, but can't make everything in one sed command without deleting every semicolon in the file. How can I do that?

Upvotes: 1

Views: 45

Answers (1)

Benjamin W.
Benjamin W.

Reputation: 52441

To run a substitution only on lines that match a pattern, you can append the substitution to an address:

sed '/^Call/s/;$//' infile

This checks if your line matches ^Call, and if so, it executes s/;$//, which removes a trailing semicolon.

Upvotes: 2

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