CODEWITHSUNDEEP
iosswifttimeoutwaitxctest
meaning-matters
meaning-matters

Reputation: 22946

How to wait in a XCTest for T seconds without timeout error?

I want to delay progression of a test for T seconds, without generating a timeout.

First I tried the obvious:

sleep(5)
XCTAssert(<test if state is correct after this delay>)

But that failed.

Then I tried: 

let promise = expectation(description: "Just wait 5 seconds")
waitForExpectations(timeout: 5) { (error) in
    promise.fulfill()

    XCTAssert(<test if state is correct after this delay>)
}

My XCTAssert() now succeeded. But waitForExpectations() failed with a timeout.

This is according to the documentation of XCTest wait functions saying:

Timeout is always treated as a test failure.

What are my options?

Upvotes: 44

Views: 28197

Answers (3)

Andr&#233; Henrique da Silva
Andr&#233; Henrique da Silva

Reputation: 541

What best worked for me was:

let timeInSeconds = 2.0 // time you need for other tasks to be finished
let expectation = XCTestExpectation(description: "Your expectation")

DispatchQueue.main.asyncAfter(deadline: .now() + timeInSeconds) {
    expectation.fulfill()
}    

wait(for: [expectation], timeout: timeInSeconds + 1.0) // make sure it's more than what you used in AsyncAfter call.

//do your XCTAssertions here
XCTAssertNotNil(value)

Upvotes: 13

A.Munzer
A.Munzer

Reputation: 1990

You can use XCTWaiter.wait functions.

For example:

let exp = expectation(description: "Test after 5 seconds")
let result = XCTWaiter.wait(for: [exp], timeout: 5.0)
if result == XCTWaiter.Result.timedOut {
    XCTAssert(<test if state is correct after this delay>)
} else {
    XCTFail("Delay interrupted")
}

Upvotes: 84

Robin Stewart
Robin Stewart

Reputation: 3883

If you know how much time something will take and simply want to wait that duration before continuing the test, you can use this one line:

_ = XCTWaiter.wait(for: [expectation(description: "Wait for n seconds")], timeout: 2.0)

Upvotes: 32

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