Reputation: 39
I know very little about javascript, but I need to do the following to include in a PHP website that I have written, where the data has to be put in a pipe delimited string. I have made a sample script which does the job..
var data_0="a";
var data_1="b";
var data_2="c";
var data_3="d";
var all="";
all = all + "|" + (data_0);
all = all + "|" + (data_1);
all = all + "|" + (data_2);
all = all + "|" + (data_3);
alert( all );
The problem is that there will be 50 or more data items. I therefore want to use a for loop to do it, and I tried this which is clearly not right..
var data_0="a";
var data_1="b";
var data_2="c";
var data_3="d";
var all="";
for (var i = 0; i <= 3; i++)
{
all = all + "|" + (data_ + i);
}
alert( all );
Can someone explain how it should be done?
Upvotes: 0
Views: 54
Reputation: 2889
var data_0="a";
var data_1="b";
var data_2="c";
var data_3="d";
var all="";
for (var i = 0; i <= 3; i++)
{
all = all + "|" + eval("data_" + i);
}
alert( all );
Upvotes: 0
Reputation: 29511
Rather than multiple variables, you need a single array
:
var data = ['a', 'b', 'c', 'd'];
To join all the elements of the array, use .join()
.
var all = data.join(', ');
Working Example:
var data = ['a', 'b', 'c', 'd'];
var all = data.join(', ');
console.log(all);
N.B. Since you are more familiar with PHP than with javascript, these two lines in javascript:
var data = ['a', 'b', 'c', 'd'];
var all = data.join(', ');
are the equivalent of these two lines in PHP:
$Data = array('a', 'b', 'c', 'd');
$All = implode(', ', $Data);
Upvotes: 1