CODEWITHSUNDEEP
rrbind
Julian
Julian

Reputation: 603

R: rbind string to factor column

I tried to rbind a row including a string to a data frame which didnt work. Code:

df1 = data.frame(id=1:5, name=c("peter","kate","lisa","daniel","paul"))
df2 = data.frame(id=5:1, age=c(11,24,25,67,2))
df3 = merge(df1,df2)
df3 = rbind(df3, c(6, "hannah", 30))
df3
str(df3)

Result:

> df1 = data.frame(id=1:5, name=c("peter","kate","lisa","daniel","paul"))
> df2 = data.frame(id=5:1, age=c(11,24,25,67,2))
> df3 = merge(df1,df2)
> df3 = rbind(df3, c(6, "hannah", 30))
Warning message:
In `[<-.factor`(`*tmp*`, ri, value = "hannah") :
  ungültiges Faktorniveau, NA erzeugt
> df3
  id   name age
1  1  peter   2
2  2   kate  67
3  3   lisa  25
4  4 daniel  24
5  5   paul  11
6  6   <NA>  30
> 
> str(df3)
'data.frame':   6 obs. of  3 variables:
 $ id  : chr  "1" "2" "3" "4" ...
 $ name: Factor w/ 5 levels "daniel","kate",..: 5 2 3 1 4 NA
 $ age : chr  "2" "67" "25" "24" ...

I looks like R made the name column a Factor column which is why it doesnt accept the string value. How do I solve this? Which is more advisable: convert the whole column into a string column (if this exists) or convert the new string into a factor? How to do this?

Thanks!

Upvotes: 0

Views: 1616

Answers (1)

jhvdz
jhvdz

Reputation: 186

A good solution is to use the dplyr package and to create tibbles instead of data frames (a tibble is a modern type of data frame which creates character variables as standard and not factors).

library(dplyr)
df1 <- tibble(id=1:5, name=c("peter","kate","lisa","daniel","paul"))
df2 <- tibble(id=5:1, age=c(11,24,25,67,2))
df3 <- left_join(df1,df2) #or merge(df1, df2) as you prefere so
df3 <- rbind(df3, c(6, "hannah", 30))
df3
str(df3)

Upvotes: 1

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