CODEWITHSUNDEEP
javajava.util.scanner
蔡王辉
蔡王辉

Reputation: 13

Why should i type six times rather than twice

i am trying to type some alphabet into two different arrs and then print some result message ,but i have to type 6 times and my result is the last twice 

    String str1[] =new String[100];
    String str2[]=new String[100];
    int count=0;
    while(true) {
        Scanner s1=new Scanner(System.in);
        if(s1.nextLine()=="END") {
            break;
        }
        str1[count]=s1.nextLine();
        Scanner s2=new Scanner(System.in);
        if(s2.nextLine()=="END") {
            break;
        }
        str2[count]=s2.nextLine();
        count++;
        System.out.println("完成第" + count + "个依赖" + "  " + s1.nextLine() +  "->" + s2.nextLine());
    }

Upvotes: 0

Views: 37

Answers (1)

Elliott Frisch
Elliott Frisch

Reputation: 201487

Every time you call nextLine you get a new line (that's why you must type everything so many times, you aren't saving the values you get). Compare String instances with .equals and you only need one Scanner, don't throw away two per loop iteration. Something like,

Scanner s1 = new Scanner(System.in);
while (true) {
    String a = s1.nextLine();
    if (a.equals("END")) {
        break;
    }
    str1[count] = a;
    String b = s1.nextLine();
    if (b.equals("END")) {
        break;
    }
    str2[count] = b;
    count++;
    System.out.println("完成第" + count + "个依赖" + "  " + a + "->" + b);
}

Upvotes: 1

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