CODEWITHSUNDEEP
javaspringspring-bootexception
Sumit Sood
Sumit Sood

Reputation: 485

bean name conflict while running the spring boot project

Background: I am working in a project named com.x.myproject. I have the dependency of two other packages com.x.document and com.x.library. both packages have the same class with name QueueHelper.

Now, In my project, I have to scan one other package com.x.security which internally scans com.x, something like that:

@SpringBootApplication
@ComponentScan(basePackages = {"com.x"})
@EnableCaching
public class Security {
.......
}

in com.x.myproject

@SpringBootApplication
@ComponentScan(basePackages = {"com.x.myproject","com.x.security"}, excludeFilters={
      @ComponentScan.Filter(type=FilterType.REGEX, pattern="com.x.document.*"),
      @ComponentScan.Filter(type=FilterType.REGEX, pattern="com.x.library.*")}) 
public class MyProject{
.......
}

It all works fine when I use excludefilters in com.x.security but I want to use it in com.x.myproject

The exception which I got is 

Annotation-specified bean name 'queueHelper' for bean class [com.x.library.utils.QueueHelper] conflicts with existing, non-compatible bean definition of same name and class [com.x.document.utils.QueueHelper]

Upvotes: 1

Views: 6902

Answers (1)

MuratOzkan
MuratOzkan

Reputation: 2730

Three answers come to my mind:

  1. Give a different names to com.x.library.utils.QueueHelper and com.x.document.utils.QueueHelper via the @Component annotation. Spring will use the simple class name by default for naming the beans. You can annotate one with @Component('libraryQueueHelper') and the other with @Component('documentQueueHelper'). However, now you'll have to give a @Qualifier(<name>) in each place you're autowiring these beans.

  2. Exclude them in your module, like you do in your question and then change their names using @Bean annotated methods within a @Configuration. When using in the third module, you'll need to use a @Qualifier to autowire the correct bean.

  3. Rename the classes. This is the best solution in this case, but since you asked this question, I guess it's not viable.

Upvotes: 5

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