CODEWITHSUNDEEP
pythoncount
mk_
mk_

Reputation: 122

How to count letters from print result?

I'm trying to compute code to find accuracy score from one-hot MNIST letters data. I want to calculate the accuracy per label in MNIST data because I use the same for precision, recall, and f1 score. y_true is dataframe [88800, 26]. First, I define true positive, true negative and the others. My code is:

for i in y_true:
x=y_true[i]
y=y_pred[i]
    for j in range(len(x)):
       if (x.values[j] == 1) and (y.values[j] == 1):
           print("True Positive", y_pred.columns[i-1])
       elif (x.values[j] == 0) and (y.values[j] == 0):
           print("True Negative", y_pred.columns[i-1])
       elif (x.values[j] == 0) and (y.values[j] == 1):
           print("False Positive", y_pred.columns[i-1])
       else:
           print("False Negative", y_pred.columns[i-1])

And the output is:

True Positive 1
True Positive 1
True Negative 1
...
True Negative 26

Till as much as the rows where 1 and 26 are each label. But, I realize, that I cannot count how much True Positive, True Negative, False Positive and False Negative per label from print result. I dunno have idea how to count it. Is it possible to count it from print result?

Upvotes: 0

Views: 158

Answers (1)

Mehrdad Pedramfar
Mehrdad Pedramfar

Reputation: 11073

You can use Counter In your code:

from collections import Counter

   c = Counter()


   for j in range(len(x)):
       if (x.values[j] == 1) and (y.values[j] == 1):
           print("True Positive", y_pred.columns[i-1])
           c.update([f'"True Positive" {y_pred.columns[i-1]}'])
       elif (x.values[j] == 0) and (y.values[j] == 0):
           print("True Negative", y_pred.columns[i-1])
           c.update([f'"True Negative" {y_pred.columns[i-1]}'])
       elif (x.values[j] == 0) and (y.values[j] == 1):
           print("False Positive", y_pred.columns[i-1])
           c.update([f'"False Positive" {y_pred.columns[i-1]}'])
       else:
           print("False Negative", y_pred.columns[i-1])
           c.update([f'"False Negative" {y_pred.columns[i-1]}'])

After this, the c will be your desired output.

For printing the output use this:

for k,v in dict(c).items():
    print(k,':',v)

Upvotes: 0

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